Question

In: Statistics and Probability

On April 12, 2018, two Giant pitchers combined to pitch a one-hitter surrendering the lone hit...

On April 12, 2018, two Giant pitchers combined to pitch a one-hitter surrendering the lone hit to pitcher batting as a pinch hitter. In 9

innings the total pitch count was 125, and 80 of these pitches were strikes.

a. Construct a 90% confidence interval for the true proportion(π)of strikes.

b. At the 5% level test the null hypothesis that the true proportion of strikes is greater than 0.60.

c. What sample size is required if you wanted to be 99% sure that the true proportion of strikes to total pitches is within 1 percentage point?

Solutions

Expert Solution

( a )

90% confidence interval is (0.569,0.711 )

( b )

Conclusion :

It is concluded that the null hypothesis Ho is not rejected. Therefore, there is not enough evidence to claim that the the true proportion of strikes is greater than 0.60.at α=0.05 significance level.

( c )

sample size ( n ) = 15287.

orchestra answered 2 years ago
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