Question

Please show the detailed calculation steps.

1) In a population of 2500 lizards the alleles determining skin colour show incomplete dominance, and the following phenotypes for each genotype are observed. 200 are homozygote C^RC^R with red colour, 1500 are homozygote C^GC^G with green colour and 800 are heterozygote C^RC^G with brown colour.

a) What are the frequencies of the C^R & C^G alleles from counting the number of alleles in the population?

b) The following season the population had grown to 3,600 and the numbers of phenotypes observed were now; 350 are homozygote C^RC^R with red colour, 1650 are homozygote C^GC^G with green colour and 1600 are heterozygote C^RC^G with brown colour.

i) Predict the phenotype percentages using the allele frequencies from the previous generation.

ii) Is the population in Hardy Weinberg equilibrium?

iii) Calculate the new allele frequencies in this population.

c) Assuming Hardy Weinberg equilibrium what would be the percentages of phenotypes in the next generation?

Answer 1

this bordered page ans is right

800 1 500 Phenotype (crenotype) | eR allele , ce allele Red color (CRCR) 200 brown color cerea 800 green color (ecreo 1000 23.00 Total population - 2500X22 Sodo a) eR allele frequency - 1000 = 0.2 che allele Frequency a 2300 2 0.46 i) B Phenotypic percentages Red colm = 200x16 21:28, 2-0-08 2500 brown color a 800016 - 250 green color a 1500 alb, Soo S700 128 5:12 - - 2 0.32 % 2 0.640 2560 :) This is Hardy Weinberg equilibrium. • Phenotypie (Grenotype) er allele ch allele red color CERCR) 1 350 brown color (eRCG) | 1600 1600 1650 Gereen color (eren) 1950 3250 Total population 36 000x2=7200 1950 "") eR allele frequency 19 2.27 7200 car allele frequency 3250 = 0.45 7200 e) and phenotypie percentages Red color = 350816 = 1.5 090 brown color 1600 X 16, 71, 71, 0.44 01 3250 1650816 Green color z F. 0.45010 16 3250 27.3

800 1 500 Phenotype (crenotype) | eR allele , ce allele Red color (CRCR) 200 brown color cerea 800 green color (ecreo 1000 23.00 Total population - 2500X22 Sodo a) eR allele frequency - 1000 = 0.2 che allele Frequency a 2300 2 0.46 i) B Phenotypic percentages Red colm = 200x16 21:28, 2-0-08 2500 brown color a 800016 - 250 green color a 1500 alb, Soo S700 128 5:12 - - 2 0.32 % 2 0.640 2560 :) This is Hardy Weinberg equilibrium. • Phenotypie (Grenotype) er allele ch allele red color CERCR) 1 350 brown color (eRCG) | 1600 1600 1650 Gereen color (eren) 1950 3250 Total population 36 000x2=7200 1950 "") eR allele frequency 19 2.27 7200 car allele frequency 3250 = 0.45 7200 e) and phenotypie percentages Red color = 350816 = 1.5 090 brown color 1600 X 16, 71, 71, 0.44 01 3250 1650816 Green color z F. 0.45010 16 3250 27.3