Mass mA =2 .1 kg traveling with velocity~ vA = (1 .2m /s)ˆ x(2.3m /s)ˆ y...

Mass mA =2 .1 kg traveling with velocity~ vA = (1 .2m /s)ˆ x(2.3m /s)ˆ y collides with mass mB =4 .2 kg at rest. After collision, mass mA leaves with velocity |~ v0A| =0 .50 m/s at an angle = 35 .

(a) Calculate the total initial momentum of the system before the collision.

(b) What is the momentum ~ p 0 A of mass mA after the collision. Give your answer in ˆ x and ˆ y component form.

(c) What is the momentum ~ p 0 B of mass mB after the collision. Give your answer in ˆ x and ˆ y component form.

(d) Assuming the collision happened over a small time period of 1.0 millisecond, what average force ~ FA acted on mass mA during the collision.

(e) Is this an elastic or inelastic collision? Justify.

Expert Solution

genius_generous answered 2 years ago

Billiard ball A of mass mA = 0.122 kg moving with speed vA = 2.80 m/s...

Billiard ball A of mass mA = 0.122 kg moving with speed vA = 2.80 m/s strikes ball B, initially at rest, of mass mB = 0.145 kg . As a result of the collision, ball A is deflected off at an angle of θ′A = 30.0∘ with a speed v′A = 2.10 m/s, and ball B moves with a speed v′B at an angle of θ′B to original direction of motion of ball A. 1) Solve these equations for...

Billiard ball A of mass mA = 0.116 kg moving with speed vA = 2.80 m/s...

Billiard ball A of mass mA = 0.116 kg moving with speed vA = 2.80 m/s strikes ball B, initially at rest, of mass mB = 0.135 kg . As a result of the collision, ball A is deflected off at an angle of θ′A = 30.0∘ with a speed v′A = 2.10 m/s, and ball B moves with a speed v′B at an angle of θ′B to original direction of motion of ball A. Solve these equations for the...

The 2-kg box is sliding along a frictionless surface at a velocity of 2m/s. It collides...

The 2-kg box is sliding along a frictionless surface at a velocity of 2m/s. It collides with a resting 5-kg box. Assuming that the collision is perfectly elastic, calculate the speed of the two boxes after the collision?

A mass m=29.0 kg slides on a frictionless track with initial velocity vA=16.5 m/s at Position...

A mass m=29.0 kg slides on a frictionless track with initial velocity vA=16.5 m/s at Position A with height hA=53.1 m. It passes over a lower hill with a height hB=26.4 m (at Position B) before stopping by running into a large spring with spring constant k=5058 N/m at Position C at height hC=23.5 m. The mass is brought to a stop at Position D, after compressing the spring by a length of d. Find the speed of the object...

Particle A (mA = 1 kg) is given initial velocity 10 m/s to the right, while...

Particle A (mA = 1 kg) is given initial velocity 10 m/s to the right, while particle B (mB = 1:5 kg) is initially at rest. The coecient of restitution for any impact between A and B is 2/3 while the coecient of restitution for impact of either particle with either wall is 5/6. The particles slide along a smooth horizontal supporting surface. Compute the percentage of the kinetic energy remaining in the system of A and B at the...

A 6.00kg mass is traveling with a velocity of 2.00m/s to the east, and an 8.00kg...

A 6.00kg mass is traveling with a velocity of 2.00m/s to the east, and an 8.00kg mass is traveling with a velocity of 5.00m/s to the west as shown in the figure. The two masses collide, and after the collision the 8.00kg mass has a velocity of 3.60m/s directed at an angle of 34° west of north. a) What is the velocity of the 6.00kg mass after the collision? b) Was the collision elastic? Show enough work to justify your...

A body of mass 15.0 kg is traveling at 5.3 m/s along the positive x-axis with...

A body of mass 15.0 kg is traveling at 5.3 m/s along the positive x-axis with no external force acting. At a certain instant an internal explosion occurs, splitting the body into two chunks of 7.5 kg mass each. The explosion gives the chunks an additional 16 J of kinetic energy. Neither chunk leaves the line of original motion. Determine the speed and direction of motion of each of the chunks after the explosion. Enter the larger velocity. Enter the...

Billiard ball A of mass 1.00 kg is given a velocity 7.10 m/s in +x direction...

Billiard ball A of mass 1.00 kg is given a velocity 7.10 m/s in +x direction as shown in the figure. Ball A strikes ball B of the same mass, which is at rest, such that after the impact they move at angles ΘA = 63.0 ° and ΘB respectively. The velocity of ball A after impact is 4.20 m/s in the direction indicated in the figure. Figure showing a layout of the problem as described in text. A) What...

A 0.20-kg softball is traveling at a velocity of 20 m/s to the east relative to...

A 0.20-kg softball is traveling at a velocity of 20 m/s to the east relative to Earth. It collides head-on with a 0.40-kg rubber ball traveling at a velocity of 10 m/s to the west. The system's kinetic energy, as measured from the Earth reference frame, decreases by 19 % because of the collision. Call the east the +x direction. a) What is the x-component of the final velocity of the softball? b) What is the x-component of the final...

A 100kg mass traveling with a velocity of 15m/s on a horizontal surface strikes a spring...

A 100kg mass traveling with a velocity of 15m/s on a horizontal surface strikes a spring with a spring constant k = 5 N/m a. Find the compression of the spring required to stop the mass if the surface is frictionless b. Find the compression of the spring if the surface is rough (0.4ku=0)

Question