A particular heart disease is said to have a prevalence of 1/1000 in a specific population....

A particular heart disease is said to have a prevalence of 1/1000 in a specific population. In a sample of 50 people chosen randomly, what is the probability that at least two people have this disease?

Expert Solution

p=1/1000 =0.001

q=1-0.001 = 0.999

n=50

P(atleast two ) =P(r>= 2) =1-P(r<2)

P=nCr p^r q^(n-r)

P(r<2) =P(r=0) +P(r=1)

= 50C0 (0.001)^0 (0.999)^50 + 50C1 (0.001)^1 (0.999)^49

=0.9512056 + 0.047607

= 0.9988

P(atleast two ) =P(r>= 2) =1-P(r<2)

=1-0.9988

= 0.0012

orchestra answered 2 years ago

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