A copper rod is sliding on two conducting rails that make an angle of 20

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A copper rod is sliding on two conducting rails that make an angle of 19o with respect to each other, as in the drawing. The rod is moving to the right with a constant speed of 0.60 m/s. A 0.45-T uniform magnetic field is perpendicular to the plane of the paper. Determine the magnitude of the average emf induced in the triangle ABC during the 5.6-s period after the rod has passed point A.

answer

from the figure, BC = AC*tan19

area of the figure, area of the tringle, A = .5*BC*AC = .5*(AC*tan19)*AC
so, avg emf = d(B*A)/dt = B*dA/dt = .5*tan19*d(AC^2)/dt = .5*tan19*2*AC*v where, v = speed of motion = 0.6 m/s

so, avg emf = .5*tan19*2*(v*t)*v = .5*tan19*2*(.6*5.6)*.6 = 0.69 V -answer

genius_generous answered 2 months ago

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