In: Statistics and Probability
A new extended-life light bulb has an average life of 750 hours, with a standard deviation of 50 hours. If the life of these light bulbs approximates a normal distribution, about what percent of the distribution will be between 650 hours and 850 hours?
µ = 750
σ = 50
we need to calculate probability for ,
650 ≤ X ≤ 850
X1 = 650 , X2 =
850
Z1 = (X1 - µ ) / σ = ( 650
- 750 ) / 50
= -2.0000
Z2 = (X2 - µ ) / σ = ( 850
- 750 ) / 50
= 2.0000
P ( 650 < X <
850 ) = P ( -2
< Z < 2.000 )
= P ( Z < 2.000 ) - P ( Z
< -2.000 ) =
0.97725 - 0.022750 =
0.9545(answer)
excel formula for probability from z score is
=NORMSDIST(Z)