USE ANOVA (ANALYSIS OF VARIANCE) SINGLE FACTOR
USE PVALUE .05
Create a Null and alternative hypothesis and fill out the anova
table by using anova in excel.
Source of Variation
Sum of Squares
Degrees of Freedom
Mean Square
F
p-value
Treatments
Blocks
Error
Total
Naturalistic Program
Physical Program
In-Class Program
51
33
44
52
36
46
33
37
45
45
35
38
57
38
41
56
32
47
37
33
43
45
36
42
51
33
44
52
36
46...
The following data was collected for a two -factor ANOVA with
three treatments and two blocks.
Treatment
1 2 3
Block
A 8 12 20
B 10 14 18
a) Complete an ANOVA table.
b) State the null and alternative hypotheses for treatments.
c) State the null and alternative hypotheses for the blocks.
d) Using the 0.05 significance level perform the test and
indicate your decision for parts b and c.
The following data are given for a two-factor ANOVA with two
treatments and three blocks.
Treatment
Block
1
2
A
43
31
B
33
22
C
46
36
Using the 0.05 significance level conduct a test of hypothesis
to determine whether the block or the treatment means
differ.
State the null and alternate hypotheses for treatments.
State the decision rule for treatments. (Round your
answer to 1 decimal place.)
State the null and alternate hypotheses for blocks....
The following data are given for a two-factor ANOVA with two
treatments and three blocks.
Treatment
Block
1
2
A
46
33
B
30
21
C
46
30
Using the 0.05 significance level conduct a test of hypothesis
to determine whether the block or the treatment means
differ.
State the null and alternate hypotheses for treatments.
State the decision rule for treatments. (Round your
answer to 1 decimal place.)
State the null and alternate hypotheses for blocks....
The following data are given for a two-factor ANOVA with two
treatments and three blocks.
Treatment
Block
1
2
A
43
35
B
31
20
C
40
36
Using the 0.05 significance level conduct a test of hypothesis
to determine whether the block or the treatment means
differ.
State the null and alternate hypotheses for treatments.
State the decision rule for treatments. (Round your
answer to 1 decimal place.)
State the null and alternate hypotheses for blocks....
The following data are given for a two-factor ANOVA with two
treatments and three blocks.
Treatment
Block
1
2
A
43
31
B
33
22
C
46
36
Using the 0.05 significance level conduct a test of hypothesis
to determine whether the block or the treatment means
differ.
State the null and alternate hypotheses for treatments.
State the decision rule for treatments. (Round your
answer to 1 decimal place.)
State the null and alternate hypotheses for blocks....
Complete the following ANOVA summary table for a two-factor
fixed-effects ANOVA, where there are five levels of factor A
(school) and four levels of factor B (curriculum design). Each cell
includes 13 students.
Source
SS
Df
Ms
F
P
a
4490.3
2.581
.038
b
2963
2.27
.081
Axb
8611.8
1.65
.079
Error
Total
120465.1
The following data are given for a two-factor ANOVA with two
treatments and three blocks. Treatment Block 1 2 A 42 32 B 33 20 C
48 39 Using the 0.05 significance level conduct a test of
hypothesis to determine whether the block or the treatment means
differ.
State the null and alternate hypotheses for treatments.
State the decision rule for treatments. (Round your answer to 1
decimal place.)
State the null and alternate hypotheses for blocks. (Round your
answer...
The following data are given for a two-factor ANOVA with two
treatments and three blocks.
Treatment
Block
1
2
A
46
31
B
37
26
C
44
35
Using the 0.05 significance level conduct a test of hypothesis
to determine whether the block or the treatment means differ.
a.
State the null and alternate hypotheses for treatments.
H0
(Click to select)The standard deviations are different.The
means are the same.The standard deviations are the same.The means
are different.
H1
(Click to...