In: Finance
[Please show all work - thanks]
Suppose an agent has $100,000 today that he wants to save for 10 years. Compare the following two savings plans.
Bank A offers the following alternative:
For the first $50,000 the agent obtains 8% p.a. (per annum) for 10 years. For the other amount he obtains 4% p.a. for the first four years. Then he obtains 1% p.a.
Bank B offers the following alternative:
The interest in year 1 is 2%, in year 2 is 4%, in year 3 is 8%, in year 4 is 20%, then for years 5 to 10 the agent obtains 3% p.a.
For both plans, interest payments are reinvested.
(a) The agent maximizes the amount at t=10. Which plan is better? How much more can he spend at t=10, if he chooses the better one?
(b) Suppose bank B wants to match the offer of bank A. Interest rates for years 2 to 10 are as above. What interest rate for the first year must bank B offer the agent so that he gets the same amount as from bank A? [4p]
A
A | |||||
Calculations For Bank A | |||||
P | i (Interest) | t (Years) | amount at end of period | Formula | |
First | 50000 | 8% | 10 | 107946.2499 | P(1+i)^t 50000*(1+8/100)^10 |
Second(first 4 years) | 50000 | i1=4% | 4 | ||
Next 6 years | 58492.93 | i2=1% | 6 | 62091.42174 | (P(1+i1)^t)((1+i2)^t) (50000*(1+4/100)^4)*((1+1/100)^6) |
Value of 100000$ after 10 years | 170037.6716 | ||||
Calculations For Bank b | |||||
Year | P | i (Interest) | t (Years) | amount at end of period | |
1 | 100000 | 2% | 1 | 102000 | P(1+i)^t 100000*(1+2/100)^1 |
2 | 102000 | 4% | 1 | 106080 | P(1+i)^t 102000*(1+4/100)^1 |
3 | 106080 | 8% | 1 | 114566.4 | P(1+i)^t 106080*(1+8/100)^1 |
4 | 114566.4 | 20% | 1 | 137479.68 | P(1+i)^t 114566.4*(1+20/100)^1 |
5 to 10 | 137479.7 | 3% | 6 | 164157.9276 | P(1+i)^t 137479.68*(1+3/100)^6 |
Value of 100000$ after 10 years | 164157.9276 |
Direct Formula | (((((100000*(1+2/100)^1)*((1+4/100)^1))*((1+8/100)^1))*((1+20/100)^1))*((1+3/100)^6)) | 164157.9276 |
Value if we go with bank A | 170037.67 | ||||
Value if we go with bank B | 164157.93 | ||||
Value of bank A is Higher so Bank A alternative is better . | |||||
He can spend 5879.74 $(170037.67-164157.93) more if he chooses Bank A over Bank B |
B
Calculations For Bank b | ||||||||||
Direct Formula | (((((100000*(1+2/100)^1)*((1+4/100)^1))*((1+8/100)^1))*((1+20/100)^1))*((1+3/100)^6)) | 164157.9 | ||||||||
This was the original situation. Now we need to change the first years's 2% interest rate so that the final amount becomes 170037.67 instead of 164157.9. That means we have to increase value of 2 to get a higher amount. We have to replace 2 With X in the above equation and we have to find the value of X | ||||||||||
(((((100000*(1+X/100)^1)*((1+4/100)^1))*((1+8/100)^1))*((1+20/100)^1))*((1+3/100)^6))=164157.9 | ||||||||||
(((((100000*(1+5.654/100)^1)*((1+4/100)^1))*((1+8/100)^1))*((1+20/100)^1))*((1+3/100)^6))=170037.67 | ||||||||||
Solving For X we get value of x = 5.654 % | So if bank B keeps interest rate for first year as 5.654% then it can give same results as bank A |