In: Statistics and Probability
Refer to the ANOVA table for this regression. |
Source | SS | d.f. | MS |
Regression | 1,035,678 | 15 | 69,045 |
Residual | 1,415,013 | 35 | 40,429 |
Total | 2,450,691 | 50 | |
(a) | State the degrees of freedom for the F test for overall significance. |
The degrees of freedom for regression are ________ and for error ______ . |
(b) |
Use Appendix F to look up the critical value of F for α = .05. (Round your answer to 2 decimal places.) |
F.05 |
(c-1) | Calculate the F statistic. (Round your answer to 4 decimal places.) |
F statistic |
(c-2) | The overall regression is significant. | ||||
|
(c-3) | The hypotheses is |
a. | H0: All the coefficients are zero (β1 = β2 = β3 = 0) vs. H1: At least one coefficient is not zero. |
b. | H0: At least one coefficient is non-zero vs. H1: All the coefficients are zero (β1 = β2 = β3 = 0) |
|
(d) | Calculate R2 and R2adj. (Round your answers to 4 decimal places.) |
R2 | |
R2adj | |
Solution:
We are given following ANOVA table:
Source | SS | d.f. | MS |
Regression | 1,035,678 | 15 | 69,045 |
Residual | 1,415,013 | 35 | 40,429 |
Total | 2,450,691 | 50 |
Part a) State the degrees of freedom for the F test for overall significance.
The degrees of freedom for regression are 15 and for error are 35.
Part b) Use Appendix F to look up the critical value of F for α = .05.
Look in F table for DF_Numerator = DF_N = 15 and DF_Denominator = DF_D = 35
at α =0.05 and find F critical value.
F critical value = 1.96
Part c-1) Calculate the F statistic.
Part c-2) The overall regression is significant.
Since F test statistic value = 1.7078 < F critical value = 1.96, we fail to reject H0: All the coefficients are zero and hence we conclude that: The overall regression is not significant.
Thus answer is: No.
Part c-3) The hypotheses is :
a) H0: All the coefficients are zero (β1 = β2 = β3 = 0) vs. H1: At least one coefficient is not zero.
Part d) Calculate R2 and R2adj.
and
n = Sample size
k = number of independent variables = 15
We know Total DF = n - 1 , then
n = Total DF + 1 = 50 + 1 = 51
Thus