In: Statistics and Probability
For the data set (−3,−1),(2,2),(5,4),(8,6),(10,11),
carry out the hypothesis test H0 β1=0 HA β1≠0
Determine the value of the test statistic and the associated p-value.
x | y | (x-x̅)² | (y-ȳ)² | (x-x̅)(y-ȳ) |
-3 | -1 | 54.7600 | 29.1600 | 39.960 |
2 | 2 | 5.7600 | 5.7600 | 5.760 |
5 | 4 | 0.3600 | 0.1600 | -0.240 |
8 | 6 | 12.9600 | 2.5600 | 5.760 |
10 | 11 | 31.3600 | 43.5600 | 36.960 |
ΣX | ΣY | Σ(x-x̅)² | Σ(y-ȳ)² | Σ(x-x̅)(y-ȳ) | |
total sum | 22.00 | 22.00 | 105.20 | 81.20 | 88.20 |
mean | 4.40 | 4.40 | SSxx | SSyy | SSxy |
Sample size, n = 5
here, x̅ = Σx / n= 4.400
ȳ = Σy/n = 4.400
SSxx = Σ(x-x̅)² = 105.2000
SSxy= Σ(x-x̅)(y-ȳ) = 88.2
estimated slope , ß1 = SSxy/SSxx = 88.2/105.2= 0.8384
slope hypothesis test
Ho: β1= 0
H1: β1╪ 0
n= 5
alpha = 0.1
estimated std error of slope =Se(ß1) = Se/√Sxx = 1.5549/√105.2= 0.1516
t stat = estimated slope/std error =ß1 /Se(ß1) = (0.8384-0)/0.1516= 5.53
Degree of freedom ,df = n-2= 3
p-value = 0.0116
decison : p-value<α , reject Ho
Conclusion: Reject Ho and conclude that slope is significantly different from zero