In: Chemistry
Calculate E
(a) Mg(s) + Sn2+(aq) Mg2+(aq) + Sn(s)
E0cell= E0cathode- E0anode
E0cell= E0Sn+2/Sn- E0Mg+2/Mg
= -0.14 - (-2.37)
E0cell = 2.23 V
now nernest equation
Ecell = E0cell -RT/nF* log [Mg+2]/[Sn+2]
Ecell = 2.23 -0.0591/2* log [0.049]/[0.037]
Ecell =2.22 V
detla G0 = -nF Ecell0
= - 2 x 96500 x 2.23
= -430.4kJ
(b) 3 Zn(s) + 2 Cr3+(aq) 3 Zn2+(aq) + 2 Cr(s)
E0cell= E0cathode- E0anode
E0cell= E0Cr+3/Cr- E0Zn+2/Zn
= -0.74 - (- 0.76)
E0cell = 0.02
Ecell = 0.02 -0.0591/2* log [0.0084]3/[0.019]2
Ecell =0.102V
detla G0 = -nF Ecell0
= - 6 x 96500 x 0.02
= -11.58kJ