Question

In: Chemistry

Calculate E

Calculate E

Solutions

Expert Solution

(a) Mg(s) + Sn2+(aq) Mg2+(aq) + Sn(s)

E0cell= E0cathode- E0anode

E0cell= E0Sn+2/Sn- E0Mg+2/Mg

          = -0.14 - (-2.37)

        E0cell = 2.23 V

now nernest equation

Ecell = E0cell -RT/nF* log [Mg+2]/[Sn+2]

Ecell = 2.23 -0.0591/2* log [0.049]/[0.037]

  Ecell     =2.22 V

detla G0 = -nF Ecell0

                  = - 2 x 96500 x 2.23

             = -430.4kJ

(b) 3 Zn(s) + 2 Cr3+(aq) 3 Zn2+(aq) + 2 Cr(s)

       E0cell= E0cathode- E0anode

       E0cell= E0Cr+3/Cr- E0Zn+2/Zn

               = -0.74 - (- 0.76)

           E0cell = 0.02

               Ecell = 0.02 -0.0591/2* log [0.0084]3/[0.019]2

  Ecell     =0.102V

detla G0 = -nF Ecell0

                   = - 6 x 96500 x 0.02

             = -11.58kJ


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