Question
In: Chemistry
1. The activation energy for the gas phase decomposition of dinitrogen pentoxide is 103 kJ. N2O5---------...
1. The activation energy for the gas phase
decomposition of dinitrogen pentoxide is
103 kJ.
N2O5---------
NO2 + 1/2 O2
The rate constant at 314 K is
2.76×10-4 /s. The rate constant will be
1.49×10-3 /s at -----------k
2. The activation energy for the gas phase
decomposition of dinitrogen pentoxide is
103 kJ.
N2O5-----------2
NO2 + 1/2 O2
The rate constant at 305 K is
8.40×10-5 /s. The rate constant will be
------- /s at 345 K.
Solutions
Expert Solution
T1 = 314K
K1 = 2.76*10^-4 s^-1
T2 =
K2 = 1.49*10^-3s^-1
Ea = 103KJ = 103000J
log(K2/K1) = Ea/2.303R [ 1/T1 - 1/T2]
log(1.49*10^-3/2.76*10^-4) = 103000/2.303*8.314 [ 1/314- 1/T2]
0.7323 = 103000/19.147142 [ 1/314- 1/T2]
0.7323*19.147142/103000 = [ 1/314- 1/T2]
0.000136 = 0.003185-1/T2
0.000136-0.003185 = -1/T2
-1/T2 = -0.003049
T2 = 1/0.003049 = 328K
2.
T1 = 305K
K1 = 8.40*10^-5 s^-1
T2 =345K
K2 =
Ea = 103KJ = 103000J
log(K2/K1) = Ea/2.303R [ 1/T1 - 1/T2]
log(K2/8.4*10^-5) = 103000/2.303*8.314 [ 1/305- 1/345]
log(K2/8.4*10^-5) = 103000/19.147142 [ 1/305- 1/345]
log(K2/8.4*10^-5) = 103000(0.00328-0.0029)/19.147142
log(K2/8.4*10^-5) = 39.14/19.147142
log(K2/8.4*10^-5) = 2.044
K2/8.4*10^-5 = 110.66
K2 = 110.86*8.4*10^-5
= 0.0093s^-1 = 9.3*10^-3s^-1 >>>>answer
queen_honey_blossom answered 3 months agoRelated Solutions
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