Question

In: Chemistry

1. The activation energy for the gas phase decomposition of dinitrogen pentoxide is 103 kJ. N2O5---------...

1. The activation energy for the gas phase decomposition of dinitrogen pentoxide is 103 kJ.

N₂O_5--------- NO₂ + 1/2 O₂
The rate constant at 314 K is 2.76×10^-4 /s. The rate constant will be 1.49×10^-3 /s at -----------k

2. The activation energy for the gas phase decomposition of dinitrogen pentoxide is 103 kJ.

N₂O_5-----------2 NO₂ + 1/2 O₂
The rate constant at 305 K is 8.40×10^-5 /s. The rate constant will be ------- /s at 345 K.

Solutions

Expert Solution

T1 = 314K

K1 = 2.76*10^-4 s^-1

T2 =

K2 = 1.49*10^-3s^-1

Ea = 103KJ = 103000J

log(K2/K1) = Ea/2.303R [ 1/T1 - 1/T2]

log(1.49*10^-3/2.76*10^-4) = 103000/2.303*8.314 [ 1/314- 1/T2]

0.7323 = 103000/19.147142 [ 1/314- 1/T2]

0.7323*19.147142/103000 = [ 1/314- 1/T2]

0.000136 = 0.003185-1/T2

0.000136-0.003185 = -1/T2

-1/T2 = -0.003049

T2 = 1/0.003049 = 328K

T1 = 305K

K1 = 8.40*10^-5 s^-1

T2 =345K

K2 =

Ea = 103KJ = 103000J

log(K2/K1) = Ea/2.303R [ 1/T1 - 1/T2]

log(K2/8.4*10^-5) = 103000/2.303*8.314 [ 1/305- 1/345]

log(K2/8.4*10^-5) = 103000/19.147142 [ 1/305- 1/345]

log(K2/8.4*10^-5) = 103000(0.00328-0.0029)/19.147142

log(K2/8.4*10^-5) = 39.14/19.147142

log(K2/8.4*10^-5) = 2.044

K2/8.4*10^-5 = 110.66

K2 = 110.86*8.4*10^-5

= 0.0093s^-1 = 9.3*10^-3s^-1 >>>>answer

queen_honey_blossom answered 1 month ago

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