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10.00g lead (II) nitrate reacts with 10.00g sodium iodide in aqueous solution to produce solid lead...

10.00g lead (II) nitrate reacts with 10.00g sodium iodide in aqueous solution to produce solid lead (II) iodide and aqueous sodium nitrate. What mass of NaI remains?

I have the answer, and the process of using stoichiometry to find it. I just do not understand the logic of the stoichiometry and why you use it to find the NaI consumed. How is do you know it is "consumed" based off of the stoichiometry you do?

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Expert Solution

So, by this approach you get to know how many moles of each reactant can actually react with each other and if there is some reactant which is present in excess then it will remain unconsumed as the other reactant has completely exhausted so no further reaction can take place .

queen_honey_blossom answered 2 years ago
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