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In: Chemistry

A volume of 1.5 L of air at 36°C is expelled from the lungs into cold surroundings at 6.4°C.


A volume of 1.5 L of air at 36°C is expelled from the lungs into cold surroundings at 6.4°C. What volume does the expelled air occupy at this temperature? The pressure and the number of gas particles do not change.

Solutions

Expert Solution

We know at constant pressure and number of moles

V1 / T1 = V2 / T2 -----(1)

T1 = 36 oC = (36 + 273) K = 309 K , V1 = 1.5 L

T2 = 6.4 oC = (6.4 + 273)K = 279.4 K

From (1) V2 = V1 * T2 / T1 = 1.5 L * 279.4 K / 309 K = 1.356 L

Volume expelled air at 6.4 oC = 1.356 L ~ 1.36 L

queen_honey_blossom answered 2 years ago
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