Please include steps 7. In a survey of n=550 randomly selected individuals, X=260 felt that Ronald...

Please include steps 7. In a survey of n=550 randomly selected individuals, X=260 felt that Ronald Reagan spent too much time away from Washington. Find a 92% confidence interval for the proportion

Expert Solution

1)Level of Significance, α = 0.08

2)

Number of Items of Interest,   x =   260
Sample Size,   n =    550

Sample Proportion ,    p̂ = x/n =    0.4727

3)z -value =   Zα/2 =    1.960   [excel formula =NORMSINV(α/2)]

4) Standard Error ,    SE = √[p̂(1-p̂)/n] =    0.021288
5) margin of error , E = Z*SE =    1.960   *   0.02129   =   0.0373

92%   Confidence Interval is
6) Interval Lower Limit = p̂ - E =    0.47273   -   0.03727   =   0.435
7) Interval Upper Limit = p̂ + E =   0.47273   +   0.03727   =   0.510

92%   confidence interval is (   0.4355   < p <    0.5100   )

orchestra answered 3 years ago

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