Question
In: Physics
Particle A of charge 3.15 10-4 C is at the origin, particle B of charge -5.94 10-4 C...
Particle A of charge 3.15 10-4 C is at the origin, particle B of charge -5.94 10-4 C is at (4.00 m, 0), and particle C of charge 1.05 10-4 C is at (0, 3.00 m). We wish to find the net electric force on C.
(a) What is the x component of the electric force
exerted by A on C?
N
(b) What is the y component of the force exerted by A on
C?
N
(c) Find the magnitude of the force exerted by B on C.
N
(d) Calculate the x component of the force exerted by B on
C.
. N
(e) Calculate the y component of the force exerted by B on
C.
. N
(f) Sum the two x components from parts (a) and (d) to
obtain the resultant x component of the electric force
acting on C.
. N
(g) Similarly, find the y component of the resultant force
vector acting on C.
. N
(h) Find the magnitude and direction of the resultant electric
force acting on C.
| magnitude | . N |
| direction | ° counterclockwise from the +x-axis |
Solutions
genius_generous answered 2 years agoRelated Solutions
Particle A of charge 3.15 10-4 C is at the origin, particle B of charge -5.94 10-4 C...
Particle A of charge 3.15 10-4 C is at the
origin, particle B of charge -5.94 10-4 C is
at (4.00 m, 0), and particle C of charge
1.05 10-4 C is at (0, 3.00 m). We wish to
find the net electric force on C.
(a) What is the x component of the electric force
exerted by A on C?
N
(b) What is the y component of the force exerted by A on
C?
N
(c) Find the magnitude of the...
Particle A of charge 3.25 ✕ 10−4 C is at the origin, particle B of charge...
Particle A of charge 3.25 ✕ 10−4 C is at the origin, particle B
of charge −6.20 ✕ 10−4 C is at (3.98 m, 0) and particle C of charge
1.25 ✕ 10−4 C is at (0, 3.38 m).
(a) What is the x-component of the electric force exerted by A
on C? N
(b) What is the y-component of the force exerted by A on C?
N
(c) Find the magnitude of the force exerted by B on C....
Particle A of charge 3.25 ✕ 10−4 C is at the origin, particle B of charge...
Particle A of charge 3.25 ✕ 10−4 C is at the origin, particle B
of charge −6.20 ✕ 10−4 C is at (3.98 m, 0) and particle C of charge
1.25 ✕ 10−4 C is at (0, 3.38 m).
(e) Calculate the y-component of the force exerted by B on C.
N
(f) Sum the two x-components to obtain the resultant x-component
of the electric force acting on C. N
(g) Repeat part (f) for the y-component. N
(h) Find...
Particle A of charge 2.97 10-4 C is at the origin, particle B of charge -6.54 10-4 C...
Particle A of charge 2.97 10-4 C is at the
origin, particle B of charge -6.54 10-4 C is
at (4.00 m, 0), and particle C of charge
1.11 10-4 C is at (0, 3.00 m). We wish to
find the net electric force on C.
(a) What is the x component of the electric force
exerted by A on C?
(b) What is the y component of the force exerted by A
on C?
(c) Find the magnitude of the force exerted...
Particle A of charge 2.97 10-4 C is at the origin, particle B of charge -5.58...
Particle A of charge 2.97 10-4 C is at the origin,
particle B of charge -5.58 10-4 C is at (4.00 m, 0), and
particle C of charge 1.10 10-4 C is at (0, 3.00 m). We
wish to find the net electric force on C.
(a) What is the x component of the electric force
exerted by A on C?
N
(b) What is the y component of the force exerted by A on
C?
N
(c) Find the...
A particle of charge -q1 is at the origin of an x axis. (a) At what...
A particle of charge -q1 is at the origin of an x axis. (a) At
what location on the axis should a particle of charge -36q1 be
placed so that the net electric field is zero at x = 4.8 mm on the
axis? (b) If, instead, a particle of charge +36q1 is placed at that
location, what is the direction (relative to the positive direction
of the x axis) of the net electric field at x = 4.8 mm?
The force exerted by an electric charge at the origin on a charged particle at a...
The force exerted by an electric charge at the origin on a
charged particle at a point (x, y, z)
with position vector r = <x,
y, z> is
F(r) =
Kr/|r|3
where K is a constant. Find the work done as the particle
moves along a straight line from (3, 0, 0) to (3, 4, 5).
. Charge q1= 1.80*10-8 C is placed at the origin O. Charge q2 = -7.20*10-8 C...
. Charge q1= 1.80*10-8 C is placed at the origin O. Charge q2 =
-7.20*10-8 C is placed at point A ( x =0.180 m) as shown in the
figures. a.
A charge q3 = 2.5 *10^-8 C is placed at point B ( x = 0.0900 m)
as shown in fig.a. Determine the net force F3 exerted on charge q3
by q1 and q2. Give your answer unit vector notation. b. The charge
q3 is now placed at point...
Suppose that a particle with charge q and mass m is initially at the origin with...
Suppose that a particle with charge q and mass m is initially at
the origin with zero velocity in the presence of external electric
and magnetic fields given by
E = (Ex, 0, Ez),
B = (0, 0, Bz).
(1) Find x(t) and draw the trajectory the particle follows in
space.
A). A positive, +4.70 C charge is placed at the origin and a –2.80 C charge...
A). A positive, +4.70 C charge is placed at the origin and a
–2.80 C charge is placed along the y-axis at y = 0.600 m. What is
the electric field at the point x = 2.00 m,
y = 0.300 m? Be sure to write your answer in unit vector
notation.
b). How much work would it take to bring a –1.9 C charge to the
point x = 2.00 m, y = 0.300 m with the two charges...
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