Question

In: Biology

You have three genes on the same chromosome - A, B and C. Each gene has...

You have three genes on the same chromosome - A, B and C. Each gene has two alleles in a dominant/recessive relationship. For these genes the homozygous recessive has the mutant phenotype for that trait, the dominant phenotype = wild type for that trait.

  • allele A is dominant to a; phenotype a = mutant for trait a; phenotype A = wild type for trait A
  • allele B is dominant to b; phenotype b = mutant for trait b; phenotype B = wild type for trait B
  • allele C is dominant to c; phenotype c = mutant for trait c; phenotype C = wild type for trait C

Note: phenotypes can be represented by single letters. For example phenotype A = genotypes Aa or AA; phenotype a = genotype aa. Assume that phenotype ab = mutant phenotype for traits a and b, and wild type phenotype for trait C.

You cross an individual heterozygote for all three genes, with an individual who is homozygote recessive for all three. Out of 10,000 offspring you get the following phenotypes and amounts:

  • phenotype a - 98
  • phenotype b - 150
  • phenotype c - 4751
  • phenotype ab - 4749
  • phenotype ac - 147
  • phenotype bc - 99
  • phenotype abc - 3
  • wild type - 3

Use this information to answer the following questions.

Based on the information given and your answer to the previous questions, what was the genotype of the heterozygous parent, in the correct order?

Select one:

a. BAc/baC

b. ABC/abc

c. AcB/aCb

d. ACB/acb

e. ABc/abC

Solutions

Expert Solution

Answer:

c. AcB/aCb

Explanation:

phenotype a – 98= aBC

phenotype b – 150=AbC

phenotype c – 4751=ABc

phenotype ab – 4749=abC

phenotype ac – 147=aBc

phenotype bc – 99=Abc

phenotype abc – 3=abc

wild type – 3=ABC

Hint: Always non- recombinant genotypes are large numbered than the recombinant genotypes.

Hence, the parental (non-recombinant) genotypes is ABc/abC

1).

If single cross over occurs between a&b

Normal order = AB/ab

After crossing over = Ab/aB

Ab Progeny= 99+150 = 249

aB progeny = 98+147 = 245

Total progeny = 10000

Total progeny = 494

Recombination frequency between a&b = (Number of recombinants / Total progeny )100

= (494/10000)100 = 4.94%

2).

If single cross over occurs between b&c

Normal order = Bc/bC

After crossing over = BC/bc

BC Progeny= 99+3 = 102

bc progeny = 98+3 = 101

Total progeny = 203

Recombination frequency between b&c = (Number of recombinants / Total progeny )100

= (203/10000)100 = 2.03%

3).

If single cross over occurs between a&c

Normal order = Ac/aC

After crossing over = AC/ac

AC Progeny= 3+150 = 153

ac progeny = 3+147 = 150

Total progeny = 303

Recombination frequency between a&c = (Number of recombinants / Total progeny )100

= (303/10000)100 = 3.03%

Recombination frequency (%)= distance between the genes (map units)

The order of genes = a-----3.03--------c-----2.03m.u.------- b

Therefore, the genotype of heterozygous parent = AcB / aCb


Related Solutions

You have three genes on the same chromosome - A, B and C. Each gene has...
You have three genes on the same chromosome - A, B and C. Each gene has two alleles in a dominant/recessive relationship. For these genes the homozygous recessive has the mutant phenotype for that trait, the dominant phenotype = wild type for that trait. allele A is dominant to a; phenotype a = mutant for trait a; phenotype A = wild type for trait A allele B is dominant to b; phenotype b = mutant for trait b; phenotype B...
You have three genes on the same chromosome - A, B and C. Each gene has...
You have three genes on the same chromosome - A, B and C. Each gene has two alleles in a dominant/recessive relationship. For these genes the homozygous recessive has the mutant phenotype for that trait, the dominant phenotype = wild type for that trait. allele A is dominant to a; phenotype a = mutant for trait a; phenotype A = wild type for trait A allele B is dominant to b; phenotype b = mutant for trait b; phenotype B...
Genes A and B are located 10cM from each other on a chromosome. Gene C is...
Genes A and B are located 10cM from each other on a chromosome. Gene C is located 25cM from gene A and 15cM from gene B. Assuming that I = 0, what is the probability that the trihybrid ABC/abc will produce an ABC gamete? I get that ABC is a result of a double crossover. A similar question was answered and said that Probability of SCO - DCO = 0.25 - 0.015 = 0.235 PLEASE EXPLAIN HOW YOU GET .25...
Suppose gene A is on the X chromosome, and genes B, C and D are on...
Suppose gene A is on the X chromosome, and genes B, C and D are on three different autosomes. Thus, A- signifies the dominant phenotype in the male or female. An equal situation holds for B-, C- and D-. The cross AA BB CC DD (female) x aY bb cc dd (male) is made. A) probability of obtaining A- individual in F1 B) probability of obtaining an a male in the F1 progeny C) Probability of A- B- C- D-...
Genes A, B, and C are located on the same chromosome with following order. Linkage map...
Genes A, B, and C are located on the same chromosome with following order. Linkage map distances among them are 11cM between A and B and 34cM between B and C. 1. When two parental genotypes were ABC/abc and abc/abc and there were 500 offspring, what would be the possible/expected genotypes and their numbers among the offspring? Assume there was no interference.
Genes A, B, and C are located on the same chromosome with following order. Linkage map...
Genes A, B, and C are located on the same chromosome with following order. Linkage map distances among them are 11cM between A and B and 34cM between B and C. 1. When two parental genotypes were ABC/abc and abc/abc and there were 500 offspring, what would be the possible/expected genotypes and their numbers among the offspring? Assume there was no interference. 1. When I=35%, what would be the numbers of recombinant phenotypes and parental phenotypes among progenies from the...
Genes A, B, and C are linked on a chromosome and found in the order A-B-C....
Genes A, B, and C are linked on a chromosome and found in the order A-B-C. Genes A and B recombine with a frequency of 9%, and genes B and C recombine at a frequency of 26%. For the cross a +b +c/abc+ × abc/abc, predict the frequency of progeny. Assume interference is zero. A) Predict the frequency of a+b+c progeny. Enter your answer to four decimal places (example 0.2356 or 0.2300). B) Predict the frequency of abc+ progeny. Enter...
Genes A, B, and C are linked on a chromosome and found in the order A-B-C....
Genes A, B, and C are linked on a chromosome and found in the order A-B-C. Genes A and B recombine with a frequency of 9%, and genes B and C recombine at a frequency of 22%. For the cross a +b +c/abc+ × abc/abc, predict the frequency of progeny. Assume interference is zero. a)Predict the frequency of a+b+c progeny. Enter your answer to four decimal places (example 0.2356 or 0.2300). B) Predict the frequency of abc+progeny. Enter your answer...
Genes A, B, and C are linked on a chromosome and found in the order A-B-C....
Genes A, B, and C are linked on a chromosome and found in the order A-B-C. Genes A and B recombine with a frequency of 6%, and genes B and C recombine at a frequency of 26%. For the cross a + b + c/abc + × abc/abc, predict the frequency of progeny. Assume interference is zero. a. Predict the frequency of a+b+c progeny. b. Predict the frequency of abc+progeny. c. Predict the frequency of a+bc+progeny d. Predict the frequency...
1. Genes A, B, and C are each located on a different chromosome type. Predict the...
1. Genes A, B, and C are each located on a different chromosome type. Predict the phenotypic ratio in the progeny of the test cross: AaBbCc X aabbcc. Assume that capital letters represent dominant alleles and lower case letters represent recessive alleles. Use the symbols “A”, “B”, & “C” to represent the dominant phenotype specified by genes A, B, & C, and the symbol “a”, “b”, & “c” to represent the recessive phenotypes. 2. If genes A & B are...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT