Find a Formula for the degree 2 Taylor polynomial
T2(x,y) at (a,b)=(pi/2,0). Do not simplify your...
Find a Formula for the degree 2 Taylor polynomial
T2(x,y) at (a,b)=(pi/2,0). Do not simplify your formula.
Use a 3d graphing tool to verify T2(x,y) does a good job of
approximating f(x,y) near (a,b)
Using the function f(x)=ln(1+x)
a. Find the 8 degree taylor polynomial centered at 0 and
simplify.
b. using your 8th degree taylor polynomial and taylors
inequality, find the magnitude of the maximum possible error on
[0,0.1]
c.approximate ln(1.1) using your 8th degree taylor polynomial.
what is the actual error? is it smaller than your estimated
error?Round answer to enough decimal places so you can
determine.
d. create a plot of the function f(x)=ln(1+x) along with your
taylor polynomial. Based on...
Find the Taylor polynomial of degree 2 centered at a = 1 for the
function f(x) = e^(2x) . Use Taylor’s Inequality to estimate the
accuracy of the approximation e^(2x) ≈ T2(x) when 0.7 ≤
x ≤ 1.3
2.
a) Find Ts(x), the third degree Taylor polynomial about x -0,
for the function e2
b) Find a bound for the error in the interval [0, 1/2]
3. The following data is If all third order differences (not
divided differences) are 2, determine the coefficient of x in P(x).
prepared for a polynomial P of unknown degree P(x) 2 1 4
I need help with both. Thank you.
Let f(x) = 1 + x − x2 +ex-1.
(a) Find the second Taylor polynomial T2(x) for f(x)
based at b = 1.
b) Find (and justify) an error bound for |f(x) − T2(x)| on the
interval
[0.9, 1.1]. The f(x) - T2(x) is absolute value.
Please answer both questions cause it will be hard to post them
separately.
1. Find the Taylor polynomial of degree ?=3 for ?(?)=?−?22
expanded about ?0=0.
2. Find the error the upper bound of the error term
?5(?) for the polynomial in part (1).
Find/calculate the 3rd degree Taylor polynomial of the function f(x) = xcos(x) that is in the heighborhood of x = 0 as well as the heighborhood of x = (π/2)
Find/calculate the 3rd degree Taylor polynomial of the function f(x) = xcos(x) that is in the heighborhood of x = 0 as well as the heighborhood of x = (π/2)