Question

In: Physics

1. A simple RC circuit consists of a 1 microF capacitor in series with a 3,000...

1. A simple RC circuit consists of a 1 microF capacitor in series with a 3,000 ohm resistor connected to a 6V battery and an open switch. Initially the capacitor is discharged. Once the switch is closed, it determines the time it takes for the voltage in the sea 3.8 V capacitor.

a. 3x10 ^ -8 s

b. 3x10 ^ 9 s

C. 3 s

d. 0.003 s

e. 3x10 ^ -9 s

QUESTION 2

1. Three 8 ohm resistors each are connected in parallel. Determine the equivalent resistance.

a. 0.054 ohms

b. 2.7 ohms

C. 0.38 ohms

d. 24 ohms

e. 0.13 ohms

QUESTION 3

1. A 5.0 microF capacitor and a resistor are connected in series to a 12V battery with an open switch on a simple RC circuit. The switch closes when t = 0. The time constant in the circuit is 4.0 s. Determine the value of the resistance.

a. 8.0x10 ^ 5 ohms

b. 60 ohms

C. 8.0x10 ^ 7 ohms

d. 8.0x10 ^ 8 ohms

e. 15 ohms

QUESTION 4

1. Kirchhoff's node law is a consequence of the law of

a. energy conservation

b. serious

C. conservation of angular momentum

d. cargo storage

e. conservation for the moment

QUESTION 5

1. A particle with mass 6.64x10 ^ -27 kg and charge of + 3.30x10 ^ -19 C is accelerated from rest through a potential difference of 2.45x10 ^ 6 V. The particle then enters a uniform magnetic field of 1.60 T. If the velocity of the particle is perpendicular to the magnetic field, determine the magnitude of the force exerted on the particle.

a. 4.09 x 10 ^ -11 N

b. 7.87 x 10 ^ -12 N

C. 1.14 x 10 ^ -10 N

d. 6.55 x 10 ^ -10 N

e. zero

Solutions

Expert Solution

1) We know,

V(c) = V(s) × [1- e^(-t/R.C)]

here, V(c) = voltage across the capacitor= 3.8 V

V(s) = supplied voltage= 6 V

t= required time.

R = resistance of the circuit= 3000 ohm

C = capacitance= 1 F = 10^(-6) F

Now, 3.8 = 6×[1-e^{-t/3000×10^(-6)}]

=> 1- e^[-t/3000×10^(-6)] = 0.6333

=> e^[-t/3000×10^(-6)] = 0.3667

=> [-t/3000×10^(-6)] = -1.0

=> t = 3×10^(-3) sec

=> t = 0.003 sec

So the correct option is : d)0.003 sec

2) Let, the equivalent resistance is R ohms

Now, 1/R = 1/8 + 1/8 + 1/8

=> 1/R = 3/8

=> R = 2.7 ohms (approx)

So the correct option is : b) 2.7 ohms

3) We know,

T = R×C

here, T = time constant = 4 sec

R= resistance

C = capacitance= 5 F = 5×10^(-6) F

Now, 4 = R×5×10^(-6)

=> R = 8×10^5 ohms

So the correct option is : a) 8×10^5 ohms.

4) Kirchhoff's law is the consequences of: a) energy conservation.

Both the KCL and KVL are fundamentally baced on energy conservation law.

[As per guidelines I'm bound to answer first four subparts of a question when more than four is posted together]

Happy chgging.


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