In: Physics
1. A simple RC circuit consists of a 1 microF capacitor in series with a 3,000 ohm resistor connected to a 6V battery and an open switch. Initially the capacitor is discharged. Once the switch is closed, it determines the time it takes for the voltage in the sea 3.8 V capacitor.
a. 3x10 ^ -8 s
b. 3x10 ^ 9 s
C. 3 s
d. 0.003 s
e. 3x10 ^ -9 s
QUESTION 2
1. Three 8 ohm resistors each are connected in parallel. Determine the equivalent resistance.
a. 0.054 ohms
b. 2.7 ohms
C. 0.38 ohms
d. 24 ohms
e. 0.13 ohms
QUESTION 3
1. A 5.0 microF capacitor and a resistor are connected in series to a 12V battery with an open switch on a simple RC circuit. The switch closes when t = 0. The time constant in the circuit is 4.0 s. Determine the value of the resistance.
a. 8.0x10 ^ 5 ohms
b. 60 ohms
C. 8.0x10 ^ 7 ohms
d. 8.0x10 ^ 8 ohms
e. 15 ohms
QUESTION 4
1. Kirchhoff's node law is a consequence of the law of
a. energy conservation
b. serious
C. conservation of angular momentum
d. cargo storage
e. conservation for the moment
QUESTION 5
1. A particle with mass 6.64x10 ^ -27 kg and charge of + 3.30x10 ^ -19 C is accelerated from rest through a potential difference of 2.45x10 ^ 6 V. The particle then enters a uniform magnetic field of 1.60 T. If the velocity of the particle is perpendicular to the magnetic field, determine the magnitude of the force exerted on the particle.
a. 4.09 x 10 ^ -11 N
b. 7.87 x 10 ^ -12 N
C. 1.14 x 10 ^ -10 N
d. 6.55 x 10 ^ -10 N
e. zero
1) We know,
V(c) = V(s) × [1- e^(-t/R.C)]
here, V(c) = voltage across the capacitor= 3.8 V
V(s) = supplied voltage= 6 V
t= required time.
R = resistance of the circuit= 3000 ohm
C = capacitance= 1 F = 10^(-6) F
Now, 3.8 = 6×[1-e^{-t/3000×10^(-6)}]
=> 1- e^[-t/3000×10^(-6)] = 0.6333
=> e^[-t/3000×10^(-6)] = 0.3667
=> [-t/3000×10^(-6)] = -1.0
=> t = 3×10^(-3) sec
=> t = 0.003 sec
So the correct option is : d)0.003 sec
2) Let, the equivalent resistance is R ohms
Now, 1/R = 1/8 + 1/8 + 1/8
=> 1/R = 3/8
=> R = 2.7 ohms (approx)
So the correct option is : b) 2.7 ohms
3) We know,
T = R×C
here, T = time constant = 4 sec
R= resistance
C = capacitance= 5 F = 5×10^(-6) F
Now, 4 = R×5×10^(-6)
=> R = 8×10^5 ohms
So the correct option is : a) 8×10^5 ohms.
4) Kirchhoff's law is the consequences of: a) energy conservation.
Both the KCL and KVL are fundamentally baced on energy conservation law.
[As per guidelines I'm bound to answer first four subparts of a question when more than four is posted together]
Happy chgging.