Error Analysis Questions: 1. Assuming the magnesium ribbon wasn't sufficiently polished to remove a coating of...

Error Analysis Questions:

1. Assuming the magnesium ribbon wasn't sufficiently polished to remove a coating of magnesium oxie on the surface. How would this affect the volume of hydrogen gas produced? Would this error cause the gas constant to be overestimated, underestimated, or remain unaffected? Please explain your reasoning.

2. Assume the water doesn't properly drain from the eudiometer tube therby leaving droplets on the sides of the glass. Would this error cause the gas constant to be overestimated, underestimated, or remain unaffected? Please explain your reasoning.

3. Imagine that as the magnesium reacts with the hydrochloric acid, a small portion of the hydrogen gas generated dissolves in the water. How would this affect the volume of H2 gas measured in the eudiometer tube? Would this error cause the gas constant to be overestimated, underestimated, or remain unaffected? Please explain your reasoning.

4. If the temperature of the hydrogen gas was underestimated, would this error cause the gas constant to be overestimated, underestimated, or remain unaffected? Please explain your reasoning.

Expert Solution

1- production of H2 remains unaffected. Magnesium ribbon is magnesium oxide, or magnesia, is a white solid mineral that occurs naturally as periclase and is a source of magnesium.A small piece of magnesium ribbon is placed in a Petri dish containing 1M hydrochloric acid bubbles of hydrogen gas formed.reaction can be written as

Mg(s) + 2 HCl(aq) ----->MgCl2(aq) + H2(g)

3- Trapped air bubbles could have caused a change in the end result.This is because trapped air bubbles in the water would be measured as less gas in the gas collecting tube, therefore having a lower answer.so,R is underestimated.

4-R= PV/nT

when T is underestimated then R is overestimated ,as per equation given above.

2-volume of H2 produce is not recorded correctly so it affected the value of gas constant .

If volume of H2 recorded is High then Value of R is overestimated & if volume of H2 recorded is low then value of R(gas constant ) is underestimated.

since R= PV/nT

queen_honey_blossom answered 4 months ago

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