Question

Given the following series: 1, 2, 5, 26, 677, ….. such that the nth term of the series equals to (n-1)th ^2 +1 and the first term of the series is 1. Write a C program using recursive function named f to compute the nth term. Use for loop to print the values of first n terms in the series. You will take input n from the user.

Example output:

Enter number of terms: *value*

*numbers here*

nth term: *value*

PLEASE DO NOT USE IOSTREAM

Answer 1

Program:

#include <stdio.h>

void f(int number) {
    int i;
    int series;
    printf("First n terms in the series : \n");
    // Loop iterates from 1 and till the number n
    for (i=1; i <= number; i++) {
        if (i == 1) { // condition to check for first term
            series = 1; // Print first term in the series as 1
        } else {
            // Other than first term (n-1)^2 + 1
            series = ((i-1)*(i-1))+1;
        }
        // Prints the series of n terms
        printf("%d\n", series);
    }
    // Prints the nth term
    printf("nth term %d\n", series);
}

int main()
{
    int number;
    // Take input for number of terms from user
    printf("Enter number of terms: ");
    scanf("%d",&number);
    // calling function to print series for n numbers
    f(number);

    return 0;
}

Output: