A beam of protons, each with energy E=20 MeV, is incident on a potential step 40...

A beam of protons, each with energy E=20 MeV, is incident on a potential step 40 MeV high. Graph using a computer the relative probability of finding protons at values of x > 0 from x = 0 to x = 5 fm.

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Expert Solution

particle with kinetic energy E strikes a barrier with height U0 > E and width L ; classically the particle cannot overcome the barrier but quantum mechanically the particle can penetrated the barrier and appear on the other side and it is known as tunneling.

The transmission coefficient T here will represent the tunniling probability of a 20 MeV protone going through the 40 MeV barrier.

This tunneling probability decays exponentially with increase of the width of the barrier and depends exponentially on width of barrier L and the difference between the particle kinetic energy and the barrier height (U0-E)1/2 and mass of the particle m1/2The formula is given as

where k2 is the decaying probability constant which tells the speed of decying probability of the tunneling. k2 is given as

genius_generous answered 2 years ago

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