In: Finance
Question Nine
Mr West decides to deposit $5000 in a BankEast Ltd account that pays 8% p.a. continuously compounded. What will be his account balance in five years?
Question Ten
Norton Industries Pty Ltd is looking at investing in Project X that is expected to generate the following cash flows each year for six years.
Year 0 |
Year 1 |
Year 2 |
Year 3 |
Year 4 |
Year 5 |
Year 6 |
$1 million |
$1.5 million |
$2 million |
$2.5 million |
$3 million |
$3.5 million |
Suppose similar investments are paying a return of 10% pa compounded semi-annually. How much should the Project X cost Norton Industries?
Please show works, don't use excel.
9.We need to use the future value for continuous compounding of the initial amount formula as follows: |
ie. FV=P*e^(n*r) |
where , FV=Future Value or balance in the a/c at end of 5 yrs. |
P=the Principal, --- $ 5000 |
e--is the mathematical constant, 2.71828 |
n= no.of years--- here 5 |
r---rate of interest -- 8% p.a |
Plugging the values , in the formula, we get the |
FV=5000*2.71828^(5*0.08)= |
7459.12 |
(Answer) |
10.Cost of project X to Norton Industries=the sum of the Present values of the cash in-flows of the 6 yrs. |
ie. PV=(CF1/(1+r)^1)+(CF2/(1+r)^2)+(CF3/(1+r)^3)+CF4/(1+r)^4)+CF5/(1+r)^5)+CF6/(1+r)^6) |
Now plugging-in the given values for CFs & semi-annual r= 10%/2 ;n=no.of semi-annual compounding periods: |
ie.PV=(1/(1+0.05)^2)+(1.5/(1+0.05)^4)+(2/(1+0.05)^6)+(2.5/(1+0.05)^8)+(3/(1+0.05)^10)+(3.5/(1+0.05)^12)= |
Solving the above, in an online equation solver, we get the PV of the investment as |
9.116283 |
millions |
OR | ||||
Using PV Factors: | ||||
Year | CF in mlns | PV F at 5% | PV at 5% | |
1 | 2 | 3 | 4 | 5=2*4 |
1 | 1 | 1/1.05^2= | 0.907029 | 0.907029 |
2 | 1.5 | 1/1.05^4= | 0.822702 | 1.234054 |
3 | 2 | 1/1.05^6= | 0.746215 | 1.492431 |
4 | 2.5 | 1/1.05^8= | 0.676839 | 1.692098 |
5 | 3 | 1/1.05^10= | 0.613913 | 1.841740 |
6 | 3.5 | 1/1.05^12= | 0.556837 | 1.948931 |
9.116283 | ||||
Cost of the investment =PV= $ 9.116283 millions |