Question

In: Physics

A sled with mass 100 kg moves in a straight line on a horizontal surface as...

A sled with mass 100 kg moves in a straight line on a horizontal surface as it is being pulled by a force 250 N at an angle of 35° with the direction of motion. A force of friction of 30 N acts on the sled. At one point in its path, its speed is 3.0 m/s; after it has traveled a distance d beyond this point, its speed is 8.0 m/s.

Use the work-energy theorem to find the total work done on the sled?

B. Find the distance d traveled by the sled.

Expert Solution

Gravitational acceleration = g = 9.81 m/s²

Mass of the sled = m = 100 kg

Force with which the sled is pulled = F = 250 N

Angle at which the force is applied = = 35^o

Component of the pull force in the direction of motion = F_x = FCos

Friction force acting on the sled = f = -30 N (Negative as it acts in the opposite direction of the motion of the sled)

Distance traveled by the sled = d

Initial speed of the sled = V₁ = 3 m/s

Speed of the sled after travelling a distance 'd' = V₂ = 8 m/s

Total work done on the sled = W

The change in kinetic energy of the sled is equal to the total work done on the sled.

W = 2750 J

Net force on the sled = F_net

F_net = 174.8 N

Total work done on the sled is equal to the net force times the distance traveled by the sled.

d = 15.73 m

A) Total work done on the sled = 2750 J

B) Distance traveled by the sled = 15.73 m

genius_generous answered 2 years ago

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