Question

In statistics, the mode of a set of values is the value that occurs most often or with the greatest frequency. Write a function that accepts as arguments the following:

• An array of integers
• An integer that indicates the number of elements in the array

The function should determine the mode of the array. That is, it should determine which value in the array occurs most often. The mode is the value the function should return. If the array has no mode (none of the values occur more than once), the function should return −1. (Assume the array will always contain nonnegative values.)
Demonstrate your pointer prowess by using pointer notation instead of array notation in this function.

can someone please help me with this in C++ programming language?

Answer 1

Thanks for the question. Below is the code you will be needing. Have used only pointers. Let me know if you have any doubts or if you need anything to change.

Thank You !

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#include <iostream>

using namespace std;

int mode(int* apointer, int size){
  
   int max_occurence=0;
   int modeNumber=0;
  
   for(int i=0; i<size; i++) {
       int current_occurence=0;
       for(int j=0; j<size; j++ ){
          
           if(*(apointer+i)==*(apointer+j)){
               current_occurence+=1;
           }
          
       }
       if(current_occurence>max_occurence){
           max_occurence=current_occurence;
           modeNumber = *(apointer+i);
       }
   }
  
   if(max_occurence!=1) return modeNumber;
   else return -1;
  
  
}

int main(){
  
   int a[] = {44,2,3,4,1,3,44,1,1,2,4,43,1,2,44,44,44};
   cout<<"Mode = "<<mode(a,sizeof(a)/sizeof(int));  
   cout<<endl;
   int b[] = {1,2,3,4,5,6,7,8,9,10,11};
   cout<<"Mode = "<<mode(b,sizeof(b)/sizeof(int));  

}

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