In: Statistics and Probability
Michael Jordan likes to take 3-point shots. In fact, the number
of 3-point shots he takes up to
time t is a Poisson process with rate 10 per hour. We assume that a
game starts at 6pm.
(a) What is the expected number of 3-point shots he takes in the
first 10 minutes of a game?
(b) What is the expected number of 3-point shots he takes between
6:20pm and 6:30pm?
(c) What is the probability that he takes exactly one 3-point shot
between 6:20pm and 6:30pm?
(d) What is the expected time he takes 5 3-point shots?
(e) Suppose he didn't take any 3-point shot in the first 10
minutes. Given that he has not taken
any 3-point shot in the first 10 minutes, what is the expected time
it takes for him to take
the first 3-point shot?
Now suppose that Michael can make any particular 3-point shot with
probability 0.4
(independently of all other shots).
(f) What it the expected number of 3-point shots he makes in the
first 30 minutes of a game?
(g) What is the probability that he makes exactly two 3-point shots
in the first 20 minutes?
(h) What is the probability that he makes at least three 3-point
shots in the first 30 minutes?
(i) What is the expected time it takes for him to successfully
score his first 3-pointer?
(j) What is the probability that he attempts three 3-point shots in
the first 15 minutes and only
one of the 3-point shots is successful?
(k) What is the probability that the first five 3-point shots are
all successful?
Meanwhile, independently of his 3-point shots, Michael takes
2-point shots according to a
Poisson process, and the mean time between two successive 2-point
shots is 3 minutes.
(l) What is the probability that he will take his first 2-point
shot before his first 3-point shot?
(m) What is the expected amount of time until he takes his third
shot (for either 2 or 3 points)?
Now suppose that Michael can make any particular 2-point shot with
probability 0.6
(independently of all other shots).
(n) What is the mean and variance of the number of points (from
either 2-point shots or 3-point
shots) he makes during the first 20 minutes of a game?
(a) What is the expected number of 3-point shots he takes in the first 10 minutes of a game?
Rate = 10 per hour = 10/6 per 10 minute = 5/3 per 10 minute
So, expected number of 3-point shots he takes in the first 10 minutes of a game = 5/3 = 1.67
(b) What is the expected number of 3-point shots he takes between
6:20pm and 6:30pm?
The time interval between 6:20pm and 6:30pm is 10 minutes.
So, expected number of 3-point shots he takes in the first 10 minutes of a game = 5/3 = 1.67
(c) What is the probability that he takes exactly one 3-point shot
between 6:20pm and 6:30pm?
Pr[X = 1] = exp(-) 1 /1! = 1.67 * exp(-1.67) = 0.3144
(d) What is the expected time he takes 5 3-point shots?
Time interval between successive poisson process follow exponential distribution with rate .
Total time interval for n poisson process will follow Gamma distribution with parameters n and .
= 5 /3 per 10 minute = 5/30 per minute = 1/6 per minute
Expected time he takes 5 3-point shots = n / = 5 / (1/6) = 30 minute
(e) Suppose he didn't take any 3-point shot in the first 10
minutes. Given that he has not taken
any 3-point shot in the first 10 minutes, what is the expected time
it takes for him to take
the first 3-point shot?
Due to memorylessness property of exponential distribution, time it takes for him to take the first 3-point shot will follow Exp( = 1/6)
Expected time it takes for him to take the first 3-point shot = 1 / = 1 / (1/6) = 6 minute