In: Statistics and Probability
NYSE 17.16 17.08 15.51 8.43 25.15
NASDAQ 15.80 16.28 16.21 17.97 7.77
Really important: Use Excel as described in “How to perform two-sample hypothesis tests” in the content area to do this problem. Be sure to save the Excel file and send it to me, named as specified I the instructions to this test.
a. State the null and alternate hypotheses. Ho:u1 ≤u2 Ha:u1>u2
b. Select alpha. 0.10, 1.645
c. Select the test statistic.
d. Formulate the decision rule.
e. What is the value of the test statistic? t= 0.579
f. Determine and interpret the effect size and p-value.
g. Draw conclusions based on statistical and practical significance.
ANSWER a-g Please and thank you!
Output using excel:
t-Test: Two-Sample Assuming Equal Variances | ||
NYSQ | NASDAQ | |
Mean | 16.666 | 14.806 |
Variance | 35.39043 | 16.16203 |
Observations | 5 | 5 |
Pooled Variance | 25.77623 | |
Hypothesized Mean Difference | 0 | |
df | 8 | |
t Stat | 0.57926 | |
P(T<=t) one-tail | 0.289178 | |
t Critical one-tail | 1.396815 | |
P(T<=t) two-tail | 0.578356 | |
t Critical two-tail | 1.859548 |
a)
Null and Alternative hypothesis:
Ho : µ1 ≤ µ2
H1 : µ1 > µ2
b)
Alpha = 0.10
c)
Test used = pooled two sample t test.
d)
Critical value, t crit = ABS(T.INV(0.1, 8)) = 1.397
Reject Ho if t > 1.397
e)
Pooled variance :
S²p = ((n1-1)*s1² + (n2-1)*s2² )/(n1+n2-2) = 25.7762
Test statistic:
t = (x̅1 - x̅2) / √(s²p(1/n1 + 1/n2 ) = 0.5793
f)
Cohen's d = (x̅1- x̅2)/√s²p = 0.366
df = n1+n2-2 = 8
p-value = T.DIST.RT(0.5793, 8) = 0.2892
g)
p-value > α, Do not reject the null hypothesis
Conclusion:
There is not enough evidence to conclude that the annual rates of return are higher on the big board at 0.10 significance level.