Question

You are given a task to parse through financial information and find the word “money” followed by “bad” 2 or more times or “money” followed by “good” once. Create a regex that can search achieve this. You can ignore spaces. Legal words in the language could be “moneybadbadbad” or “moneygood”

Answer 1

The following is the code for above question. Here we used regex to solve the problem

import re
#input text to search for example
txt1="he is a moneybadbadbad boy"
txt2="he is a moneybad boy"
txt3="he is a moneygoodgood boy"
txt4="he is a moneygood boy"
#the word boundary \b is used for moneygood to match exactly once and badbad+ is used to match bad more than 2 times
x1=re.search(r'(\bmoneygood\b)|((money{1})badbad+)',txt1) 
x2=re.search(r'(\bmoneygood\b)|((money{1})badbad+)',txt2)
x3=re.search(r'(\bmoneygood\b)|((money{1})badbad+)',txt3)
x4=re.search(r'(\bmoneygood\b)|((money{1})badbad+)',txt4)
#print and test all matches
print(x1)
print(x2)
print(x3)
print(x4)

I am also attaching the output and code screenshot for your reference.

Output and code screenshot:

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