In: Statistics and Probability
You wish to test the following claim (HaHa) at a significance
level of α=0.001α=0.001. For the context of this problem,
μd=PostTest−PreTestμd=PostTest-PreTest where the first data set
represents a pre-test and the second data set represents a
post-test. (Each row represents the pre and post test scores for an
individual. Be careful when you enter your data and specify what
your μ1μ1 and μ2μ2 are so that the differences are computed
correctly.)
Ho:μd=0Ho:μd=0
Ha:μd≠0Ha:μd≠0
You believe the population of difference scores is normally
distributed, but you do not know the standard deviation. You obtain
the following sample of data:
pre-test | post-test |
---|---|
53.7 | 159.8 |
47.5 | 33.5 |
46.9 | 9 |
54.6 | 102.5 |
55.6 | 77.2 |
48.5 | 117.2 |
49.7 | 30.7 |
56.1 | -3 |
54 | 11.5 |
50.3 | 23.6 |
47.5 | 59.5 |
46.6 | 8.7 |
49 | 39.9 |
53.2 | 85.6 |
47.1 | 45.3 |
43.6 | -42.9 |
55.4 | 41.4 |
58.8 | 102.4 |
47.2 | -16.5 |
What is the test statistic for this sample?
test statistic = (Report answer accurate to 4 decimal
places.)
What is the p-value for this sample?
p-value = (Report answer accurate to 4 decimal
places.)
Number | Post Test | Pre Test | Difference | |
159.8 | 53.7 | 106.1 | 12167.2511 | |
33.5 | 47.5 | -14 | 95.9368698 | |
9 | 46.9 | -37.9 | 1135.33529 | |
102.5 | 54.6 | 47.9 | 2714.95845 | |
77.2 | 55.6 | 21.6 | 665.911607 | |
117.2 | 48.5 | 68.7 | 5315.1774 | |
30.7 | 49.7 | -19 | 218.884238 | |
-3 | 56.1 | -59.1 | 3013.43213 | |
11.5 | 54 | -42.5 | 1466.48687 | |
23.6 | 50.3 | -26.7 | 506.013186 | |
59.5 | 47.5 | 12 | 262.610554 | |
8.7 | 46.6 | -37.9 | 1135.33529 | |
39.9 | 49 | -9.1 | 23.9584488 | |
85.6 | 53.2 | 32.4 | 1339.94529 | |
45.3 | 47.1 | -1.8 | 5.78529086 | |
-42.9 | 43.6 | -86.5 | 6772.42371 | |
41.4 | 55.4 | -14 | 95.9368698 | |
102.4 | 58.8 | 43.6 | 2285.34319 | |
-16.5 | 47.2 | -63.7 | 3539.62371 | |
Total | 885.4 | 965.3 | -79.9 | 42760.3495 |
Ho:μd=0
Ha:μd≠0
Test Statistic :-
t = -0.3761
Test Criteria :-
Reject null hypothesis if
Result :- Fail to reject null hypothesis
Decision based on P value
P - value = P ( t > 0.3761 ) = 0.7112
Reject null hypothesis if P value <
level of significance
P - value = 0.7112 > 0.001 ,hence we fail to reject null
hypothesis
Conclusion :- Fail to reject null hypothesis
There is insufficient evidence to support the claim that :μd≠0.