Determine the mass of chloride (MW = 35.45 g/mol ) in grams present in 100 mL...

Determine the mass of chloride (MW = 35.45 g/mol ) in grams present in 100 mL of a 0.187 M solution of aqueous FeCl3 (iron(III) chloride).

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Expert Solution

number of moles of FeCl3= M * V

=0.187 M* 0.1 L {Since volume= 100mL= 0.1 L}

= 0.0187 mol

1 mol of FeCl3 gives 3 moles of Cl-

So,number of moles of Cl - = 3*number of moles of FeCl3

= 3* 0.0187

=0.0561 mol

Molar mass of Cl - = 35.45 g/mol

mass of Cl- = number of moles of Cl- * molar mass

= 0.0561*35.45

= 1.99 g

Answer: 1.99 g

queen_honey_blossom answered 2 weeks ago

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