Question

SIGNS = '03,21-04,19=ARI;04,20-05,20=TAU;05,21-06,21=GEM;06,22-07,22=CAN;' + \ '07,23-08,22=LEO;08,23-09,22=VIR;09,23-10,23=LIB;10,24-11,20=SCO;' + \ '11,21-12,21=SAG;12,22-01,20=CAP;01,21-02,21=AQU;02,22-03,20=PIS;' def find_astrological_sign(month, date): ''' (int, int) -> str Given two int values representing a month and a date, return a 3-character string that gives us what star sign a person born in that month and on that date belongs to. Use the SIGNS string (already defined for you at the top of this file) to figure this out. NOTE: A lot of string slicing to do here. The information for each sign is exactly 16 characters long. >>> find_astrological_sign(8, 24) 'VIR' >>> find_astrological_sign(1, 15) 'CAP' How can this be done using lists?

Answer 1

Answer:

Code:

SIGNS = '03,21-04,19=ARI;04,20-05,20=TAU;05,21-06,21=GEM;06,22-07,22=CAN;' +

'07,23-08,22=LEO;08,23-09,22=VIR;09,23-10,23=LIB;10,24-11,20=SCO;' +

'11,21-12,21=SAG;12,22-01,20=CAP;01,21-02,21=AQU;02,22-03,20=PIS;'

def find_astrological_sign(month, date):

signs_list = SIGNS.split(";")

for sign in signs_list:

if sign!="":

m1 = int(sign[0:2])

d1 = int(sign[3:5])

m2 = int(sign[6:8])

d2 = int(sign[9:11])

if(m1==month and d1<=date) or (m2==month and d2>=date):

return sign[12:]

print(find_astrological_sign(8, 24))

print(find_astrological_sign(1, 15))