In: Physics
The specific heat capacity of water is = c = 1 calorie/gram oF.
Volume of water = 1 gallon = 3.7854 liters.
And as the density of water is approximately = 1g/ml, so the mass of water present is -
Mass = Volume x density
= (3.7854 x 1000 ml) x (1g/ml)
So, m = 3785.4 g
The change in temperature = T = 1 oF
Thus, amount of heat energy required = q = m*c*T
= (3785.4*1*1)
= 3785.4 cal
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