Question

Explain the following code using comments next to the code:

void foo() {
uint8_t a=2;
uint8_t b[]={b0, b1, b2}; // They are the last three digits of your A#
uint8_t* c=b;
uint8_t* d=&a;

Answer 1

#include <stdio.h>
#include <stdint.h>

int main() {
        
        uint8_t a;
        for(int i=0;i<300;i++){
                a=i;
                printf("%d \n",a);
        }
    return 0;
}

1
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252
253
254
255
0
1
2
3
...

void foo(){  // foo() is a function of type void. It does not return anything
        uint8_t a=2;   // a is a varible of 8 bit unsigned integer type
        
        uint8_t b[]={b0, b1, b2}; // b[] is an 8 bit unsigned integer type array which 
                                  //currently stores three 8 bit unsigned integer value 
                                  // of the elements b0, b1, b2
        
        uint8_t* c=b;            // c is an 8 bit unsigned integer type pointer to array b[]
                                 // initially c points to base address of b[] i.e. b[0]
                                 
                                 
        uint8_t* d=&a;           // d is an 8 bit unsigned integer type pointer 
                                // it stores the address of a 
}

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