Question

In: Physics

A railroad freight car rolls on a track at 2.65 m/s toward two identical coupled freight...

A railroad freight car rolls on a track at 2.65 m/s toward two identical coupled freight cars, which are rolling in the same direction as the first, but at a speed of 1.20 m/s. The first reaches the second two and all couple together. The mass of each is 2.30 ✕ 10⁴ kg.

(a) What is the speed (in m/s) of the three coupled cars after the first couples with the other two? (Round your answer to at least two decimal places.)

(b)Find the (absolute value of the) amount of kinetic energy (in J) converted to other forms during the collision.

Expert Solution

Let the mass of 1 railroad freight car be

Given mass,

In question 1 freight car collide and couple with 2 identical coupled freight cars.

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Mass of the first freight car,

Initial velocity of the first freight car,

Mass of identical coupled freight cars,

Initial velocity of the coupled freight cars,

==============

During collision momentum is conserved

Initial momentum = Final momentum

Cancel mass m

(a) ANSWER:

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(b) Find the amount of kinetic energy lost during collision

Kinetic energy lost = Initial kinetic energy- Final kinetic energy.

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Initial kinetic energy,

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Final kinetic energy,

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(b) ANSWER:

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genius_generous answered 6 months ago

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