Question

class Point3d { public: Point3d(double x, double y, double z);

Point3d(const point3d& p);

void setX(double x);

void setY(double y);

void setZ(double z);

double getX() const;

double getY() const;

double getZ() const;

point3d& operator=(const point3d& rhs); private: double x; double y; double z;

};

Given the Point class above, complete the following:

1. Write just the signature for the overloaded addition operator that would add the respective x,y, and z from two point3d objects.

2. What is the output of the code (assuming copy constructor and copy assignment operators are properly implemented).

point3d p1{3,4,5};

point3d p2{p1};

p2.setY(2*p2.getX());

point3d* p3 = new point3d{p1.getX(), p2.getY(), p2.getZ()};

p3 = &p1; cout << *p3.getZ() << endl;

p1.setY(2*p1.getZ());

p3.setX(p2.getZ());

p1 = p2; cout << p1.getX() + “, ” p1.getY() + “, ” p1.getZ() << endl;

cout << p2.getX() + “, ” p2.getY() + “, ” p2.getZ() << endl;

cout << p3.getX() + “, ” p3.getY() + “, ” p3.getZ() << endl;

delete p3;

Answer 1

Given code:

.

class Point3d
{
public:
Point3d(double x, double y, double z);
Point3d(const Point3d &p);
void setX(double x);
void setY(double y);
void setZ(double z);
double getX() const;
double getY() const;
double getZ() const;
Point3d &operator=(const Point3d &rhs);

private:
double x;
double y;
double z;
};

.

Q->1. Write just the signature for the overloaded addition operator that would add the respective x,y, and z from two Point3d objects.
Answer:
Point3d &operator+(const Point3d other);
.

Q->2. What is the output of the code (assuming copy constructor and copy assignment operators are properly implemented).

Point3d p1{3, 4, 5};

Point3d p2{p1};

// p1 and p2 are both same points (3,4,5) till this line

// set p2.y = 2 * 3 = 6

p2.setY(2 * p2.getX());

// now p2 will be (3,6,5)

Point3d *p3 = new Point3d{p1.getX(), p2.getY(), p2.getZ()};

// p3 points to (3,6,5) till this line

p3 = &p1;

// p3 will be same as p1 due to above line ie (3,4,5)

cout << (*p3).getZ() << endl;

// prints 5

p1.setY(2 * p1.getZ());

// above line sets p1.y = 2 * 5 = 10

// now p1 is (3,10,5)

p3->setX(p2.getZ());

// above line sets p3.x = 5, it also modifies p1

// now p3 will be (5,4,5)

p1 = p2;

// now p1 = p2 = (3,6,5)

// and p3 points to p1, it also points to (3,6,5)

// print all points

cout << p1.getX() + ", " p1.getY() + ", " p1.getZ() << endl;

cout << p2.getX() + ", " p2.getY() + ", " p2.getZ() << endl;

cout << p3.getX() + ", " p3.getY() + ", " p3.getZ() << endl;

// above lines prints:

// 3, 6, 5

// 3, 6, 5

// 3, 6, 5

delete p3;

.

Final output through running program::

.