The power (in watts) used to move air out of the lungs is equal to the...

The power (in watts) used to move air out of the lungs is equal to the air pressure (in N/m²) multiplied by the air flow rate (in m³/s). For quiet breathing (where p = 100 N/m² and flow rate = 100 cm³/s or 1.0 x 10^-4 m³/s), the power involved = 0.01 W ; for loud singing (where p = 4000 N/m² and flow rate = 400 cm³/s or 4.0 x 10⁴ m³/s), the power involved = 1.6 W.

In problem P7 (above), we determined that the total power involved in moving the air at a pressure of 4000 N/m² (loud singing) = 1.6 W. The fraction (in %) of this total power that is converted into and radiated as sound = _______ %.

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genius_generous answered 5 months ago

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