Question

The following picture represents a sample of gas at a pressure of 1 atm, a volume of 1 L, and a temperature of 25 ?C

What would happen to the pressure if the volume were reduced to 0.4L and the temperature increased to 260?C?

Answer 1

We know that PV = nRT

Where P,V,n,R,T are the pressure , volume , number of moles , gas constant & temperature respectively.

Since the same amount of gas under go volume , pressure & temperature change

Where

P₁ = initial pressure = 1 atm

V₁ = initial volume = 1 L

T₁ = initial temperature = 25 ^oC = 25 + 273 = 298 K

P₂ = final pressure = ?

V₂ = final volume = 0.4 L

T₂ = final temperature = 260 ^oC = 260 + 273 = 533 K

Plug these values in the above equation we get

                                                                      P₂ = 4.5 atm

Therefore the final pressure is 4.5 atm