Question

In: Statistics and Probability

Five states were randomly selected and their members in the State or Federal parliament are noted...

Five states were randomly selected and their members in the State or Federal parliament are noted below. APC: 33, 10, 14, 12, 10; PDP: 19, 15, 10, 20, 20. At α=0.10, can it be concluded that there is a dependent relationship between the state and the political party affiliation of their representatives? Choose ALL the relevant options

Solutions

Expert Solution

Claim : There is a dependent relationship between the state and the political party affiliation of their representatives.

Hypothesis :  

H0: There is a not dependent relationship between the state and
      the political party affiliation of their representatives.

H1: There is a dependent relationship between the state and
the political party affiliation of their representatives.

Given values are observed frequency .

1 2 3 4 5 Total
APC 33 10 14 12 10 79
PDP 19 15 10 20 20 84
Total 52 25 24 32 30 163

Form the observed frequency find expected frequency .

Expected frequency =( row total * column total ) / Grand Total .

1 2 3 4 5
APC (79*52)/163=25.20 (79*25)/163=12.12 (79*24)/163=11.63 (79*32)/163=15.51 (79*30)/30=14.54
PDP (84*52)/163=26.80 (84*25)/163=12.88 (84*24)/163=12.37 (84*32)/163=16.49 (84*30)/163=15.46

Formula for test statistics :

    where Oi = observed frequency , Ei = expected frequency .

So here , test statistics = .

Find critical value : Df = ( # of row -1) (# of column -1) =(2-1) (5-1)=1*4=4

                               and here use level of significance = 0.05 .

                               Since critical value = 2.776

Decision : Test statistics value =    > critical value =2.776 ; since reject H0.

Conclusion : At 5% level of significance , is is sufficient eveidence to conclude that there is a
                dependent relationship between the state and the political party affiliation of their
                representatives.

orchestra answered 2 years ago
Next > < Previous

Related Solutions

I. The members of a very large health club were observed on a randomly selected day....
I. The members of a very large health club were observed on a randomly selected day. The distribution of times they spent that day at the health club was found to have a mean of 91.8 minutes and a standard deviation of 16.2 minutes. Suppose these values of the mean and standard deviation hold true for all members of this club. 1. Find the minimum percentage of this health club's members who spend time at this health club between 51.3...
2-Sample Tests: Thirty crew members of this expedition were randomly selected to be studied in each...
2-Sample Tests: Thirty crew members of this expedition were randomly selected to be studied in each of three different experiments, for a total of 90 crew members randomly selected. A group of 30 volunteers were used, for control groups, in each experiment where 2-samples were used. The goal was to determine if the differences between the experimental and control groups was sufficiently large enough to justify further study or action (neurological, psychological, or physical). Hypothesis Test 1: Neurological Assessment ->...
2-Sample Tests: Thirty crew members of this expedition were randomly selected to be studied in each...
2-Sample Tests: Thirty crew members of this expedition were randomly selected to be studied in each of three different experiments, for a total of 90 crew members randomly selected. A group of 30 volunteers were used, for control groups, in each experiment where 2-samples were used. The goal was to determine if the differences between the experimental and control groups was sufficiently large enough to justify further study or action (neurological, psychological, or physical). Hypothesis Test 1: Neurological Assessment ->...
16 out of 151 randomly selected faculty members who were surveyed at a community college know...
16 out of 151 randomly selected faculty members who were surveyed at a community college know sign language. What would be a 90% confidence interval for the proportion of all faculty members at the community college who know sign language? (Round to three decimal places and enter the interval in the format (lower bound, upper bound).)
In a survey of 1000 randomly selected adults in the United States, participants were asked what...
In a survey of 1000 randomly selected adults in the United States, participants were asked what their most favorite and what their least favorite subject was when they were in school (Associated Press, August 17, 2005). In what might seem like a contradiction, math was chosen more often than any other subject in both categories! Math was chosen by 228 of the 1000 as the favorite subject, and it was also chosen by 366 of the 1000 as the least...
In a recent Gallup poll, 1003 randomly selected adults in the United States were asked if...
In a recent Gallup poll, 1003 randomly selected adults in the United States were asked if they have a gun in their home, and 37.2% of them answered “yes”. Construct a 95% confidence interval estimate of the percentage of all adults who would answer “yes” when asked if they have a gun in their home. [Write your answer as a complete sentence]
In a survey of 1000 randomly selected adults in the United States, participants were asked what...
In a survey of 1000 randomly selected adults in the United States, participants were asked what their most favorite and what their least favorite subject was when they were in school (Associated Press, August 17, 2005). In what might seem like a contradiction, math was chosen more often than any other subject in both categories! Math was chosen by 222 of the 1000 as the favorite subject, and it was also chosen by 362 of the 1000 as the least...
Randomly selected students were given five seconds to estimate the value of a product of numbers...
Randomly selected students were given five seconds to estimate the value of a product of numbers with the results shown below. Estimates from students given 1×2×3×4×5×6×7×81×2×3×4×5×6×7×8: 169, 500, 5635, 10000, 45000, 50, 5000, 800, 1000, 200169, 500, 5635, 10000, 45000, 50, 5000, 800, 1000, 200 Estimates from students given 8×7×6×5×4×3×2×18×7×6×5×4×3×2×1: 400, 40320, 500, 350, 450, 225, 1500, 428, 550, 40000400, 40320, 500, 350, 450, 225, 1500, 428, 550, 40000 Use a 0.050.05 significance level to test ?0:?21=?22H0:σ12=σ22 vs. ??:?21≠?22Ha:σ12≠σ22 :...
Randomly selected students were given five seconds to estimate the value of a product of numbers...
Randomly selected students were given five seconds to estimate the value of a product of numbers with the results shown below. Estimates from students given 1×2×3×4×5×6×7×8: 10000, 2040, 750, 4000, 42200, 6000, 1500, 5000, 500, 5000 Estimates from students given 8×7×6×5×4×3×2×1: 100000, 10000, 52836, 1200, 450, 100000, 200, 2050, 1500, 400 Use a 0.05 significance level to test the following claims: Claim: the two populations have equal variances. The test statistic is   The larger critical value is   The conclusion is...
Fifteen randomly selected college students were asked to state the number of hours they slept the...
Fifteen randomly selected college students were asked to state the number of hours they slept the previous night. The resulting data are 5, 10, 7, 8, 6, 7, 7, 6, 6, 9, 4, 3, 8, 9, 7. Find the following. (Round your answers to two decimal places.) (a) Variance s2, using formula below $ s^2 = \dfrac{\sum{(x - \overline{x})^2}}{n - 1}$ s2 = (b) Variance s2, using formula $ s^2 = \dfrac{\sum{x^2} - \dfrac{(\sum{x})^2}{n}}{n - 1} $ s2 = (c)...
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT