Question

In: Other

A plant to make 30 000 t y-1 of glycerine and comprising 11 process steps was...

A plant to make 30 000 t y-1 of glycerine and comprising 11 process steps was built in the UK five years ago, with a total investment cost of GBP 48 million. A new plant for the production of 50 000 t y-1 of glycerine is now to be built near Ankara, Turkey. Because of more stringent international legislation, new glycerine plants require additional pollution control equivalent to 3 further process steps. Estimate the total investment cost in TRY (Turkish Lira) of such a plant using the data below.

Scale factor = 0.6

DATA

8 y ago

5 y ago

Now

Cost index: Turkey

150

223

342

Cost index: UK

201

262

285

Location factor, Turkey/UK

0.82

not available

not available

Exchange rate, TRY/GBP

2.43

2.77

2.82

Solutions

Expert Solution

Amanda K answered 1 year ago
Next > < Previous

Related Solutions

The following T-accounts represent November activity. Materials Inventory EB (11/30) 56,400 Work-In-Process Inventory BB (11/1) 32,600...
The following T-accounts represent November activity. Materials Inventory EB (11/30) 56,400 Work-In-Process Inventory BB (11/1) 32,600 Dir.Materials 86,200 Finished Goods Inventory EB (11/30) 101,000 Cost of Goods Sold Manufacturing Overhead Control Applied Manufacturing Overhead 264,000 Wages Payable Sales Revenue 725,400 Additional Data Materials of $113,600 were purchased during the month, and the balance in the Materials Inventory account increased by $11,000. Overhead is applied at the rate of 150 percent of direct labor cost. Sales are billed at 180 percent...
The following T-accounts represent November activity. Materials Inventory EB (11/30) 56,200 Work-In-Process Inventory BB (11/1) 32,600...
The following T-accounts represent November activity. Materials Inventory EB (11/30) 56,200 Work-In-Process Inventory BB (11/1) 32,600 Dir.Materials 85,400 Finished Goods Inventory EB (11/30) 99,000 Cost of Goods Sold Manufacturing Overhead Control Applied Manufacturing Overhead 262,500 Wages Payable Sales Revenue 681,700 Additional Data Materials of $115,100 were purchased during the month, and the balance in the Materials Inventory account increased by $10,200. Overhead is applied at the rate of 150 percent of direct labor cost. Sales are billed at 170 percent...
The following T-accounts represent November activity. Materials Inventory EB (11/30) 57,100 Work-In-Process Inventory BB (11/1) 32,900...
The following T-accounts represent November activity. Materials Inventory EB (11/30) 57,100 Work-In-Process Inventory BB (11/1) 32,900 Dir.Materials 86,800 Finished Goods Inventory EB (11/30) 101,000 Cost of Goods Sold Manufacturing Overhead Control Applied Manufacturing Overhead 270,000 Wages Payable Sales Revenue 643,200 Additional Data (a) Materials of $113,800 were purchased during the month, and the balance in the Materials Inventory account increased by $11,300. (b) Overhead is applied at the rate of 150 percent of direct labor cost. (c) Sales are billed...
At 30 June 2019, Boxes Ltd reported the following assets. Land $50 000 Plant 250 000...
At 30 June 2019, Boxes Ltd reported the following assets. Land $50 000 Plant 250 000 Accumulated Depreciation (50 000) Goodwill 8 000 Inventories 40 000 Cash 2 000 All assets are measured using the cost model. At 30 June 2019, the recoverable amount of the entity, considered to be a single CGU, was $272 000. For the period ending 30 June 2020, the depreciation charge on plant was $18 400. If the plant had not been impaired the charge...
y′ = t, y(0) = 1, solution: y(t) = 1+t2/2 y′ = 2(t + 1)y, y(0)...
y′ = t, y(0) = 1, solution: y(t) = 1+t2/2 y′ = 2(t + 1)y, y(0) = 1, solution: y(t) = et2+2t y′ = 5t4y, y(0) = 1, solution: y(t) = et5 y′ = t3/y2, y(0) = 1, solution: y(t) = (3t4/4 + 1)1/3 For the IVPs above, make a log-log plot of the error of Backward Euler and Implicit Trapezoidal Method, at t = 1 as a function of hwithh=0.1×2−k for0≤k≤5.
y′ = t, y(0) = 1, solution: y(t) = 1+t2/2 y′ = 2(t + 1)y, y(0)...
y′ = t, y(0) = 1, solution: y(t) = 1+t2/2 y′ = 2(t + 1)y, y(0) = 1, solution: y(t) = et2+2t y′ = 5t4y, y(0) = 1, solution: y(t) = et5 y′ = t3/y2, y(0) = 1, solution: y(t) = (3t4/4 + 1)1/3 For the IVPs above, make a log-log plot of the error of Explicit Trapezoidal Rule at t = 1 as a function ofhwithh=0.1×2−k for0≤k≤5.
fourier transform of the following with steps: x(t) = z(t) + z(t - 30) x(t) =...
fourier transform of the following with steps: x(t) = z(t) + z(t - 30) x(t) = z(2*t) + z(t + 30) x(t) = z^(2)(t)
1. Consider the initial value problem y′ =1+y/t, y(1)=3 for1≤t≤2. • Show that y(t) = t...
1. Consider the initial value problem y′ =1+y/t, y(1)=3 for1≤t≤2. • Show that y(t) = t ln t + 3t is the solution to the initial value problem. • Write a program that implements Euler’s method and the 4th order Runke-Kutta method for the above initial value problem. Use your program to solve with h = 0.1 for Euler’s and h = 0.2 for R-K. • Include a printout of your code and a printout of the results at each...
Solve equations 1.) y'-y=t/y 2.) y'-(1/t)y=y2sin(t) 3.) y'+y=y2cos(t) 4.) y'-2y=cos(t)/(y1/2)
Solve equations 1.) y'-y=t/y 2.) y'-(1/t)y=y2sin(t) 3.) y'+y=y2cos(t) 4.) y'-2y=cos(t)/(y1/2)
On 1 January 2008, a company bought plant at a price of $500 000. The plant...
On 1 January 2008, a company bought plant at a price of $500 000. The plant was to be depreciated using the straight line method over its useful life of 5 years (after which it was estimated that it would have no residual value). For tax purposes, wear and tear is allowed on the following basis: 50% in the first year 30% in the second year 20% in the third year On 31 December 2011 the plant was sold for...
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT