Question

submit the following files:

• Main.java

Consider the following code:

import java.util.Scanner;

public class Main {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

String input = "";

System.out.println("Enter the first number: ");

input = in.nextLine();

int a = 0;

int b = 0;

a = Integer.parseInt(input);

System.out.println("Enter the second number: ");

input = in.nextLine();

b = Integer.parseInt(input);

int result = 0;

result = a/b;

System.out.println("a/b : " + result);

}

Copy the code to your Main.java file and run it with the following inputs:

1. 34 and 0;

2. ‘Thirty-four’ as the first input.

What prevented the program from running successfully?

Update the code, so that it can handle cases a) and b).

Please note the following:

• You have to use try-catch to handle exceptions. You will get zero credit otherwise;

• To determine exception classes, that you need to catch, use error message from the respective case (a) and b)). Hint: to handle String-to-integer conversion, use NumberFormatException;

• Exceptions should be caught so that:

  • Code never crashes due to non-numeric input (both for first and second values);

  • Code never crashes due to division by zero;

  • If non-numeric value is entered for a or b, program should output "Error: entered value is not an integer number. Exiting..." and exit (use System.exit(0); to exit);

  • If zero value is entered for b, program should output " Error: cannot divide by zero. Exiting..." and exit (use System.exit(0); to exit);

• Hints: Use 3 try-catch blocks in total. Try block should only contain the command, that can throw an exception.

PLEASE FOLLOW ALL THE INSTRUCTIONS PRECISELY

Answer 1

Updated code:

import java.util.Scanner;

public class Main {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

String input = "";

System.out.println("Enter the first number: ");

input = in.nextLine();

int a = 0;

int b = 0;
try{

a = Integer.parseInt(input);

}
catch(NumberFormatException e)
{
System.out.println("Error: entered value is not an integer number. Exiting...");
System.exit(0);
}
System.out.println("Enter the second number: ");

input = in.nextLine();

try{

b = Integer.parseInt(input);

}
catch(NumberFormatException e)
{
System.out.println("Error: entered value is not an integer number. Exiting...");
System.exit(0);
}

int result = 0;
try{

result = a/b;

}
catch(ArithmeticException e)
{
System.out.println("Error: cannot divide by zero. Exiting...");
System.exit(0);
}

System.out.println("a/b : " + result);

}}

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