In: Finance
Some time ago, Julie purchased eleven acres of land costing $14,890. Today, that land is valued at $71,805. How long has she owned this land if the price of the land has been increasing at 6 percent per year?
27.13 years
26.51 years
27.00 years
26.72 years
26.67 years
Solution: | ||
Answer is 3rd option 27.00 years | ||
Working Notes: | ||
Future value = Present Value (1+r)^t | ||
Future value = today value of land = $71,805 | ||
Present value = value of land when purchased = $14,890 | ||
Time t = period of time ago purchased = t years | ||
rate r = increasing rate per year = 6% per year = 0.06 | ||
Future value = Present Value (1+r)^t | ||
71,805 =14,890 (1+0.06)^t | ||
(1.06)^t = (71805/14890) | ||
(1.06)^t =4.822364003 | ||
taking log on both side | ||
(1.06)^t =4.822364003 | ||
Log(1.06)^t = Log(4.822364003) | ||
using relation loga^b = b x Log a | ||
t x Log(1.06) = Log(4.822364003) | ||
t= Log(4.822364003)/Log(1.06) | ||
t= 27.00006428 years | ||
t= 27.00 years | ||
Hence | it was purchased 27.00 years ago | |
Please feel free to ask if anything about above solution in comment section of the question. |