In: Finance
Some time ago, Julie purchased eleven acres of land costing $14,890. Today, that land is valued at $71,805. How long has she owned this land if the price of the land has been increasing at 6 percent per year?
27.13 years
26.51 years
27.00 years
26.72 years
26.67 years
| Solution: | ||
| Answer is 3rd option 27.00 years | ||
| Working Notes: | ||
| Future value = Present Value (1+r)^t | ||
| Future value = today value of land = $71,805 | ||
| Present value = value of land when purchased = $14,890 | ||
| Time t = period of time ago purchased = t years | ||
| rate r = increasing rate per year = 6% per year = 0.06 | ||
| Future value = Present Value (1+r)^t | ||
| 71,805 =14,890 (1+0.06)^t | ||
| (1.06)^t = (71805/14890) | ||
| (1.06)^t =4.822364003 | ||
| taking log on both side | ||
| (1.06)^t =4.822364003 | ||
| Log(1.06)^t = Log(4.822364003) | ||
| using relation loga^b = b x Log a | ||
| t x Log(1.06) = Log(4.822364003) | ||
| t= Log(4.822364003)/Log(1.06) | ||
| t= 27.00006428 years | ||
| t= 27.00 years | ||
| Hence | it was purchased 27.00 years ago | |
| Please feel free to ask if anything about above solution in comment section of the question. | ||