Question

In: Statistics and Probability

Homework #3-2 a) (Use software for this problem) Four independent samples are collected form four normally...

Homework #3-2

a) (Use software for this problem) Four independent samples are collected form four normally distributed populations. The data are:

        Group 1:       12     11     14     10     12     10

        Group 2:       14     12     16     15

        Group 3:       17     18     20     22     23

        Group 4:       10     9       13     13

The SST is equal to 305.68. Conduct a test of the null hypothesis that the group means are equal. Use a 5% significance level.

b) (Use software for this problem) The following pairs of observations were collected.

        X       1       2       3       4       5

        Y       2       6       4       10     15

a.     Plot the values of X and Y. What relationship does the scatter diagram suggest?

b.    Find the least squares line

c.    Find the predicted value for each value of X

d.    Find the residual for each predicted value of Y.

e.    Verify that the sum of the residuals in part e is zero.

Solutions

Expert Solution

a).

One factor ANOVA

Mean

n

Std. Dev

11.5

6

1.52

Group1

14.3

4

1.71

Group2

20.0

5

2.55

Group3

11.3

4

2.06

Group4

14.3

19

4.12

Total

ANOVA table

Source

SS

   df

MS

F

   p-value

Treatment

246.68

3

82.228

20.91

0.0000129

Error

59.00

15

3.933

Total

305.68

18

H1: At least one pair of population means are different

Calculated F=120.91, P=0.00001 which is < 0.05 level of significance.

The null hypothesis is rejected.

The data indicate there is a significant difference among the three groups.

b).

a).

the plot suggests there is positive relation exists between x and y.

b).

Regression Analysis

0.840

n

5

r

0.916

k

1

Std. Error of Estimate

2.394

Dep. Var.

y

Regression output

confidence interval

variables

coefficients

std. error

   t (df=3)

p-value

95% lower

95% upper

Intercept

a =

-1.600

x

b =

3.000

0.757

3.962

.0287

0.590

5.410

ANOVA table

Source

SS

df

MS

F

p-value

Regression

90.000

1  

90.000

15.70

.0287

Residual

17.200

3  

5.733

Total

107.200

4  

Regression line y= -1.6+3.0*x

c).d).e). all the 3 results given in the table.

x

y

Predicted

Residual

1

2.0

1.4

0.6

2

6.0

4.4

1.6

3

4.0

7.4

-3.4

4

10.0

10.4

-0.4

5

15.0

13.4

1.6

Total

0.0


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