In: Statistics and Probability
A study was conducted that measured the total brain volume (TBV) (in mm3) of patients that had schizophrenia and patients that are considered normal. Table #1 contains the TBV of the normal patients and Table #2 contains the TBV of schizophrenia patients ("SOCR data Oct2009," 2013).
Table #1: Total Brain Volume (in mm3) of Normal Patients
1663407 |
1583940 |
1299470 |
1535137 |
1431890 |
1578698 |
1453510 |
1650348 |
1288971 |
1366346 |
1326402 |
1503005 |
1474790 |
1317156 |
1441045 |
1463498 |
1650207 |
1523045 |
1441636 |
1432033 |
1420416 |
1480171 |
1360810 |
1410213 |
1574808 |
1502702 |
1203344 |
1319737 |
1688990 |
1292641 |
1512571 |
1635918 |
Table #2: Total Brain Volume (in mm3) of Schizophrenia Patients
1331777 |
1487886 |
1066075 |
1297327 |
1499983 |
1861991 |
1368378 |
1476891 |
1443775 |
1337827 |
1658258 |
1588132 |
1690182 |
1569413 |
1177002 |
1387893 |
1483763 |
1688950 |
1563593 |
1317885 |
1420249 |
1363859 |
1238979 |
1286638 |
1325525 |
1588573 |
1476254 |
1648209 |
1354054 |
1354649 |
1636119 |
Is there enough evidence to show that the patients with schizophrenia have less TBV on average than a patient that is considered normal? Test at the 10% level.
(i) Let ?1= mean TBV of patients that are considered normal. Let ?2 = mean TBV of patients that had schizophrenia. Which of the following statements correctly defines the null hypothesis HO?
A. ?1 + ?2= 0
B. ?1 – ?2< 0 (?1 < ?2)
C. ?1 ? ?2 > 0 (?1 > ?2)
D. ?1 ? ?2 = 0 (?1 = ?2)
Enter letter corresponding to correct answer
(ii) Let ?1= mean TBV of patients that are considered normal. Let ?2 = mean TBV of patients that had schizophrenia. Which of the following statements correctly defines the alternate hypothesis HA?
A. ?1 ? ?2 = 0 (?1 = ?2)
B. ?1 – ?2< 0 (?1 < ?2)
C. ?1 ? ?2 > 0 (?1 > ?2)
D. ?1 + ?2= 0
Enter letter corresponding to correct answer
(iii) Enter the level of significance ? used for this test:
Enter in decimal form. Examples of correctly entered answers: 0.01 0.02 0.05 0.10
(iv) For sample from population with mean = ?1 : Determine sample mean x??1 and sample standard deviation s1iv For sample from population with mean = ?1 : Determine sample mean x¯1 and sample standard deviation s1
Enter sample mean in integer form (no decimals), then comma, then sample standard deviation in integer form. Examples of correctly entered answers:
13145,1211
-112845,13187
(v) For sample from population with mean = ?2 : Determine sample mean x??2 and sample standard deviation s2v For sample from population with mean = ?2 : Determine sample mean x¯2 and sample standard deviation s2
Enter sample mean in integer form (no decimals), then comma, then sample standard deviation in integer form. Examples of correctly entered answers:
13145,1211
-112845,13187
(vi) Determine degrees of freedom df :
Enter value in decimal form rounded down to nearest whole number. Examples of correctly entered answers:
2 3 16 110
(vii) Determine test statistic:
Enter value in decimal form rounded to nearest ten-thousandth. Examples of correctly entered answers:
0.0104 3.0370 16.5000 110.0819
(viii) Using tables, calculator, or spreadsheet: Determine and enter p-value corresponding to test statistic.
Enter value in decimal form rounded to nearest ten-thousandth. Examples of correctly entered answers:
0.0001 0.0021 0.0305 0.6004 0.8143 1.0000
(ix) Comparing p-value and ? value, which is the correct decision to make for this hypothesis test?
A. Reject Ho
B. Fail to reject Ho
C. Accept Ho
D. Accept HA
Enter letter corresponding to correct answer.
(x) Select the statement that most correctly interprets the result of this test:
A. The result is not statistically significant at .10 level of significance. Sufficient evidence exists to support the claim that patients with schizophrenia have less TBV on average than a patient that is considered normal.
B. The result is not statistically significant at .10 level of significance. There is not enough evidence to support the claim that patients with schizophrenia have less TBV on average than a patient that is considered normal.
C. The result is statistically significant at .10 level of significance. Sufficient evidence exists to support the claim that patients with schizophrenia have less TBV on average than a patient that is considered normal.
D. The result is statistically significant at .10 level of significance. There is not enough evidence to support the claim that patients with schizophrenia have less TBV on average than a patient that is considered normal.
Following is the output of descriptive statistics:
Descriptive statistics | ||
X1, normal patients | X2, schizophrenia patients | |
count | 32 | 31 |
mean | 14,63,339.22 | 14,51,293.19 |
sample standard deviation | 1,25,458.28 | 1,71,932.23 |
sample variance | 15,73,97,79,000.05 | 29,56,06,90,486.83 |
minimum | 1203344 | 1066075 |
maximum | 1688990 | 1861991 |
range | 485646 | 795916 |
So we have
(i)
The null hypothesis is:
(ii)
The alternative hypothesis is
(iii)
The level of significance: 0.10
(iv-v)
(vi)
Here degree of feedom will be
The critical value for 61 degree of freedom and 0.10 level of signficance are: +/- 1.670
(vii)
The pooled standard deviation:
-------------
So standard error for difference in population mean is
The t-statistics will be
(viii)
The p-value is: 0.3756
(ix)
B. Fail to reject Ho
(x)
B. The result is not statistically significant at .10 level of significance. There is not enough evidence to support the claim that patients with schizophrenia have less TBV on average than a patient that is considered normal.