Question

In: Statistics and Probability

A study was conducted that measured the total brain volume (TBV) (in mm3) of patients that...

A study was conducted that measured the total brain volume (TBV) (in mm3) of patients that had schizophrenia and patients that are considered normal. Table #1 contains the TBV of the normal patients and Table #2 contains the TBV of schizophrenia patients ("SOCR data Oct2009," 2013).

Table #1: Total Brain Volume (in mm3) of Normal Patients

1663407

1583940

1299470

1535137

1431890

1578698

1453510

1650348

1288971

1366346

1326402

1503005

1474790

1317156

1441045

1463498

1650207

1523045

1441636

1432033

1420416

1480171

1360810

1410213

1574808

1502702

1203344

1319737

1688990

1292641

1512571

1635918

Table #2: Total Brain Volume (in mm3) of Schizophrenia Patients

1331777

1487886

1066075

1297327

1499983

1861991

1368378

1476891

1443775

1337827

1658258

1588132

1690182

1569413

1177002

1387893

1483763

1688950

1563593

1317885

1420249

1363859

1238979

1286638

1325525

1588573

1476254

1648209

1354054

1354649

1636119

Is there enough evidence to show that the patients with schizophrenia have less TBV on average than a patient that is considered normal? Test at the 10% level.

(i) Let ?1= mean TBV of patients that are considered normal. Let ?2 = mean TBV of patients that had schizophrenia. Which of the following statements correctly defines the null hypothesis HO?

A.  ?1 + ?2= 0

B.  ?1 – ?2< 0 (?1 < ?2)

C.  ?1 ? ?2 > 0 (?1 > ?2)

D.  ?1 ? ?2 = 0 (?1 = ?2)

Enter letter corresponding to correct answer

(ii)   Let ?1= mean TBV of patients that are considered normal. Let ?2 = mean TBV of patients that had schizophrenia. Which of the following statements correctly defines the alternate hypothesis HA?

A.  ?1 ? ?2 = 0 (?1 = ?2)

B.  ?1 – ?2< 0 (?1 < ?2)

C.  ?1 ? ?2 > 0 (?1 > ?2)

D.  ?1 + ?2= 0

Enter letter corresponding to correct answer

(iii) Enter the level of significance ? used for this test:

Enter in decimal form. Examples of correctly entered answers:  0.01    0.02    0.05    0.10

(iv) For sample from population with mean = ?1 : Determine sample mean x??1 and sample standard deviation s1iv  For sample from population with mean = ?1 :          Determine sample mean x¯1 and sample standard deviation s1

Enter sample mean in integer form (no decimals), then comma, then sample standard deviation in integer form. Examples of correctly entered answers:  

13145,1211

-112845,13187

(v) For sample from population with mean = ?2 : Determine sample mean x??2 and sample standard deviation s2v  For sample from population with mean = ?2 :       Determine sample mean x¯2 and sample standard deviation s2

Enter sample mean in integer form (no decimals), then comma, then sample standard deviation in integer form. Examples of correctly entered answers:  

13145,1211

-112845,13187

(vi) Determine degrees of freedom df :

Enter value in decimal form rounded down to nearest whole number. Examples of correctly entered answers:

2 3 16 110

(vii) Determine test statistic:

Enter value in decimal form rounded to nearest ten-thousandth. Examples of correctly entered answers:

0.0104      3.0370        16.5000        110.0819

(viii) Using tables, calculator, or spreadsheet: Determine and enter p-value corresponding to test statistic.

Enter value in decimal form rounded to nearest ten-thousandth. Examples of correctly entered answers:

0.0001     0.0021     0.0305     0.6004      0.8143    1.0000

(ix) Comparing p-value and ? value, which is the correct decision to make for this hypothesis test?  

A. Reject Ho

B. Fail to reject Ho

C. Accept Ho

D. Accept HA

Enter letter corresponding to correct answer.

  (x) Select the statement that most correctly interprets the result of this test:

A. The result is not statistically significant at .10 level of significance. Sufficient evidence exists to support the claim that patients with schizophrenia have less TBV on average than a patient that is considered normal.

B. The result is not statistically significant at .10 level of significance. There is not enough evidence to support the claim that patients with schizophrenia have less TBV on average than a patient that is considered normal.

C. The result is statistically significant at .10 level of significance. Sufficient evidence exists to support the claim that patients with schizophrenia have less TBV on average than a patient that is considered normal.

D. The result is statistically significant at .10 level of significance. There is not enough evidence to support the claim that patients with schizophrenia have less TBV on average than a patient that is considered normal.

Solutions

Expert Solution

Following is the output of descriptive statistics:

Descriptive statistics
X1, normal patients   X2, schizophrenia patients
count 32 31
mean 14,63,339.22 14,51,293.19
sample standard deviation 1,25,458.28 1,71,932.23
sample variance 15,73,97,79,000.05 29,56,06,90,486.83
minimum 1203344 1066075
maximum 1688990 1861991
range 485646 795916

So we have

(i)

The null hypothesis is:

(ii)

The alternative hypothesis is

(iii)

The level of significance: 0.10

(iv-v)

(vi)

Here degree of feedom will be

The critical value for 61 degree of freedom and 0.10 level of signficance are: +/- 1.670

(vii)

The pooled standard deviation:

-------------

So standard error for difference in population mean is

The t-statistics will be

(viii)

The p-value is: 0.3756

(ix)

B. Fail to reject Ho

(x)

B. The result is not statistically significant at .10 level of significance. There is not enough evidence to support the claim that patients with schizophrenia have less TBV on average than a patient that is considered normal.


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