In: Math
Participant |
Stress Level (X) |
Test Score (Y) |
1 |
18 |
6 |
2 |
3 |
17 |
3 |
12 |
9 |
4 |
8 |
22 |
5 |
15 |
7 |
6 |
7 |
11 |
What's the slope of this data (round to two decimal places)?
What's the Y intercept (round to two decimal places)?
What's the predicted test score for a stress level of 10 (round to two decimal places)?
What's the error of participant 5's score (round to two decimal places)?
What's the standard error of the estimate?
What is the coefficient of determination?
X | Y | XY | X^2 | Y^2 |
18 | 6 | 108 | 324 | 36 |
3 | 17 | 51 | 9 | 289 |
12 | 9 | 108 | 144 | 81 |
8 | 22 | 176 | 64 | 484 |
15 | 7 | 105 | 225 | 49 |
7 | 11 | 77 | 49 | 121 |
From the above calculated table and formula we get the value are as:
n | 6 |
sum(XY) | 625.00 |
sum(X) | 63.00 |
sum(Y) | 72.00 |
sum(X^2) | 815.00 |
sum(Y^2) | 1060.00 |
Numerator | -786.00 |
Denominator | 1040.72 |
r | -0.7552 |
b | -0.8534 |
a | 20.9609 |
Slope of the dats is -0.85
y intercept is 20.96
When x = 10
predicted test score = 20.96 - 0.85 * 10
= 12.46
|
From the above table we get the value are as;
Error of participants 5 = 1.3447
Standard error of estimate = sqrt(14.0337) = 3.7462
Coefficient of determination formula are as:
From the above calculated table and value we get,
r = -0.7552