Question

In: Statistics and Probability

Almost all U.S. light-rail systems use electric cars that run on tracks built at street level....

Almost all U.S. light-rail systems use electric cars that run on tracks built at street level. The Federal Transit Administration claims light-rail is one of the safest modes of travel, with an accident rate of .99 accidents per million passenger miles as compared to 2.29 for buses. The following data show the miles of track and the weekday ridership in thousands of passengers for six light-rail systems.

City Miles of Track Ridership (1000s)
Cleveland 14 17
Denver 16 37
Portland 37 83
Sacramento 20 33
San Diego 46 77
San Jose 30 32
St. Louis 33 44
  1. Use these data to develop an estimated regression equation that could be used to predict the ridership given the miles of track.

    Compute b0 and b1 (to 2 decimals).
    b1 =
    b0 =

    Complete the estimated regression equation (to 2 decimals).

  2. Compute the following (to 1 decimal):
    SSE =
    SST =
    SSR =
    MSE =

  3. What is the coefficient of determination (to 3 decimals)? Note: report r2 between 0 and 1.


    Does the estimated regression equation provide a good fit?
    SelectYes, it even provides an excellent fitYes, it provides a good fitNo, it does not provide a good fitItem 10
  4. Develop a 95% confidence interval for the mean weekday ridership for all light-rail systems with 30 miles of track (to 1 decimal).
    (  ,  )
  5. Suppose that Charlotte is considering construction of a light-rail system with 30 miles of track. Develop a 95% prediction interval for the weekday ridership for the Charlotte system (to 1 decimal).
    (  ,  )

    Do you think that the prediction interval you developed would be of value to Charlotte planners in anticipating the number of weekday riders for their new light-rail system?
    SelectYes, because this interval has high accuracyYes, because this interval has high confidenceYes, because this interval has both high accuracy and high confidenceNo, because this interval is too wideNo, because this interval has low confidenceItem 15

Solutions

Expert Solution

X Y XY X² Y²
14 17 238 196 289
16 37 592 256 1369
37 83 3071 1369 6889
20 33 660 400 1089
46 77 3542 2116 5929
30 32 960 900 1024
33 44 1452 1089 1936
Sample size, n = 7
Ʃ x = 196
Ʃ y = 323
Ʃ xy = 10515
Ʃ x² = 6326
Ʃ y² = 18525
x̅ = 28
y̅ = 46.14285714
SSxx = Ʃx² - (Ʃx)²/n = 838
SSyy = Ʃy² - (Ʃy)²/n = 3620.857143
SSxy = Ʃxy - (Ʃx)(Ʃy)/n = 1471

a) b1 = SSxy/SSxx = 1.75537 =  1.76
b0 = y̅ -b1* x̅ = -3.0075 = -3.01

Regression equation:

ŷ = -3.01 + 1.76 x

b)

SSE = SSyy -b*SSxy = 1039.708 = 1038.7
SST = SSyy = Ʃy² - (Ʃy)²/n = 3620.8571 = 3620.9
SSR = b*SSxy = 2582.1492 = 2582.1
MSE = SSE/(n-2) = 207.7

c) Coefficient of determination, R² = SSR/SST = 0.713

Yes, it provides a good fit.

------------------

d) Predicted value at X = 30          
ŷ = -3.0075 + 1.7554 * 30 = 49.65  

Standard error, se = √(SSE/(n-2)) = 14.4132

At α = 0.05 and df = n-2 = 5, critical value, t_c = T.INV.2T(0.05, 5 ) = 2.5706

95%Confidence interval for the mean weekday ridership for all light-rail systems with 30 miles of track :
Lower limit = ŷ - tc*se*√((1/n) + ((x-x̅)²/(SSxx))) = 35.4
Upper limit = ŷ + tc*se*√( (1/n) + ((x-x̅)²/(SSxx))) = 63.9

------------------

e) 95% prediction interval for the weekday ridership for the Charlotte system:

Lower limit = ŷ - tc*se*√(1 + (1/n) + ((x-x̅)²/(SSxx))) = 10.0
Upper limit = ŷ + tc*se*√(1 + (1/n) + ((x-x̅)²/(SSxx))) = 89.3

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