Question

Remember: if p < .05, then you reject the null hypothesis and accept the alternative hypothesis. If p > .05, then you accept the null hypothesis and reject the alternative hypothesis. In a two-tailed hypothesis test, the null hypothesis means there is no significant difference between the groups, then in the alternative hypothesis you state there is a significant difference between the groups. 1. Watch the below video on the Chi-Square Method. Video: Chi-Square Test A. Identify what the null and alternative hypothesis are in the chi-square method video example (use a two-tailed hypothesis for both null and alternative). B. Identify the P value in the video example C. Use hypothesis testing to either accept or reject the null or alternative hypothesis. D. Interpret the results from the video and how they can be applied in real life. 2. Watch the video below on the ANOVA method. Video: ANOVA Excel A. Identify what the null and alternative hypothesis are in the ANOVA method video example (use a two-tailed hypothesis for both null and alternative). B. Identify the P value in the video example C. Use hypothesis testing to either accept or reject the null or alternative hypothesis. D. Interpret the results and how they can be applied in real life. 3. How can you use the Chi-Square and ANOVA statistical methods in your future career (200 word minimum).

Answer 1

1. chisquare test

A.There are two types of chi square tests one is chisquare test of goodness of fit and the other one is chi square test of independece of attributes

in case of chi square test of goodness of fit the null hypothesis H0 is there is no significance difference between observed and expected frequencies of a characteristic

where as the alternative hypothesis is there is some significant difference between observed and expected frequencies of a charecteristic

B. If the value of p< 0.05 we reject the null hypothesis otherwise we accept the alternative hypothesis

C. in this test the test statistic to test the hypothesis is ² =    / E

which follows chi square distribution with n-1 degrees of freedom

D. .If the value of chisquare is less than the the critical value of chisquare at 5% level of significance for n-1 degrees of freedom we accept the null hypothesis otherwise we accept the alternative hypothesis

this test we can apply in real life to compare the observed and expected frequencies of several characteristics

2. ANOVA or analysis of variance it is useful for seperating the variance arised from one group of causes to the variance arised from other group of causes

It is useful for testing the significance of a treatment effect in an experiment

A. the null hypothesis is the treatment is not significant i.e the treatment is not causing any significant variability

the alternative hypothesis is the treatment is showing some significant effect

B. if the value of p < 0.5 we reject the null hypothesis otherwise we accept the accept it

C. for testing the significance of the treatment we can construct F test statistic

F test statistic = S_e² / S_t²  it follows F distribution with (K-1,N-K) degrees of freedom at 5% level of significance

If the value of F is less than the critical value of F or the value of P>0.05 we accept the nullhypothesis otherwise we reject it

ANOVA we can apply in real life for testing thesignificant effect of various treatments on the dependent variables