In: Statistics and Probability
Identify the null hypothesis, alternative hypothesis, test
statistic, P-value, conclusion about the null hypothesis, and final
conclusion that addresses the original claim.
Various temperature measurements are recorded at different times
for a particular city. The mean of 20°C is obtained for 60
temperatures on 60 different days. Assuming that test the claim
that the population mean is 22°C . Use a 0.05 significance level.
Testing Hypothesis Z-Table
Null Hypothesis H0: = 22
Altenative Hypothesis Ha: 22
Sample mean, = 20
Population Standard deviation = 1.5
Since we know the true population standard deviation we will conduct one sample z test.
Standard error of mean, SE = / = 1.5 / = 0.1936492
Test statistic, z = ( - ) / SE = (20 - 22) / 0.1936492 = -10.328
For two-tail test, p-value = 2 * p(z < -10.328) = 0.0000
Since, p-value is less than 0.05 significance level, we reject null hypothesis H0.
We conclude that there is significant evidence from the sample data that true mean temperature of the city is different from 22 degree Celsius.