a box of mass m = 66.0 kg (initially at rest) is pushed a distance d...

a box of mass m = 66.0 kg (initially at rest) is pushed a distance d = 54.0 m across a rough warehouse floor by an applied force of FA = 218 N directed at an angle of 30.0° below the horizontal. The coefficient of kinetic friction between the floor and the box is 0.100. Determine the following. (For parts (a) through (d), give your answer to the nearest multiple of 10.) * I already solved parts b and c so I didn't include them.

a)work done by the applied force WA =

d)work done by the force of friction Wf =

e) Calculate the net work on the box by finding the sum of all the works done by each individual force. WNet = J

f)Now find the net work by first finding the net force on the box, then finding the work done by this net force. WNet = J

Solutions

Expert Solution

Part a)

Clearly Net Applied Force is given by the x component. Which is given as,

Applied Force =

Work done by the applied force is given as the force multiplied by the distance travelled by object.

Work done by Applied force ,

Putting values we have,

So work done by the applied force is, 10190 Joule.

Part d)

Work done by force of friction can be calculated by multipying frictional force by the distance.

So, Work done by friction is 4080 Joule.

Part e and f

Please note 1 Newton meter = 1 Joule.

In case of any difficulty, Please comment.

Thank you.

genius_generous answered 1 month ago

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