In: Math
**Only answer G-J, I already did A-F**
2. Measuring the height of a California redwood tree is very difficult because these trees grow to heights over 300 feet. People familiar with these threes understand that the height of a California redwood tree is related to other characteristics of the tree, including the diameter of the tree at the breast height of a person (in inches), the thickness of the bark of the tree (in inches), the distance from the closest neighboring tree (in yards), and the number of the other trees neighboring within 10 yards from the tree. Using the data set (Redwood.xlsx), conduct a regression analysis by answering the following questions.
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(g) Determine the coefficient of determination, ? 2 , and interpret its meaning (f) At the level ? = 0.10, is there a significant relationship between the thickness and the pressure? Answer based on the t test in the p-value approach
(h) Determine the adjusted coefficient of determination, adjusted ? 2 , and interpret its meaning
(i) Evaluate the linearity assumption using the residual plot about the independent variable for diameter
(j) Evaluate the normality assumption using the normal probability plot
f) SUMMARY OUTPUT | ||||||
Regression Statistics | ||||||
Multiple R | 0.890143976 | |||||
R Square | 0.792356299 | |||||
Adjusted R Square | 0.740445373 | |||||
Standard Error | 23.59964085 | |||||
Observations | 21 | |||||
ANOVA | ||||||
df | SS | MS | F | Significance F | ||
Regression | 4 | 34004.19695 | 8501.049236 | 15.26376757 | 2.53617E-05 | |
Residual | 16 | 8911.088769 | 556.943048 | |||
Total | 20 | 42915.28571 | ||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | |
Intercept | 66.53179445 | 22.53752929 | 2.952044725 | 0.009370562 | 18.75436668 | 114.3092222 |
Diameter at breast height | 2.047792982 | 0.465597442 | 4.39820497 | 0.000448911 | 1.060770498 | 3.034815466 |
Bark thickness | 14.59276252 | 7.718269335 | 1.890678063 | 0.076918199 | -1.769237547 | 30.95476258 |
Distance from the closest | -0.945471598 | 2.172038096 | -0.435292364 | 0.669165076 | -5.549986669 | 3.659043473 |
Trees within 10 yard | 1.140592423 | 3.075882526 | 0.37081794 | 0.715636928 | -5.379987243 | 7.661172089 |
g)
R^2 = 0.792356299
this means 79.24 % of variation in y is explained by this model
h) adjusted R^2 = 0.740445373
The adjusted R2 tells you the percentage of variation explained by only the independent variables that actually affect the dependent variable