In: Statistics and Probability
A sample of 20 items provides a sample standard deviation of 5. Compute the 95% confidence interval estimate of the population variance.
Select one:
a. 23.61 ≤≤ σσ2 ≤≤ 72.16
b. 14.46 ≤≤ σσ2 ≤≤ 53.31
c. 2.08 ≤≤ σσ2 ≤≤ 16.7
d. 16.35 ≤≤ σσ2 ≤≤ 33.32
The 95% confidence interval estimate of the population variance
2 is:
n = sample size
s2= sample variance &
2n-1,
/2
and
2n-1,1-
/2
is chi-square table value at (n-1) degrees of freedom and
level of Significance for two tailed test.
In the given example,
n= sample size= 20
S = sample standard deviation= 5
S2= sample variance=25
=
5% level of Significance=0.05
From chi-square table,
2n-1,
/2=
220-1,0.05/2=
219,0.025=32.852
2n-1,1-
/2=
220-1,1-0.05/2=
219,0.975=8.91
The 95% confidence interval estimate of the population variance
2 is:
The 95% confidence interval estimate of the population variance
2 is :
The option (b) is the correct option.