Question

In: Statistics and Probability

A sample of 20 items provides a sample standard deviation of 5. Compute the 95% confidence...

A sample of 20 items provides a sample standard deviation of 5. Compute the 95% confidence interval estimate of the population variance.

Select one:

a. 23.61 ≤≤ σσ2 ≤≤ 72.16

b. 14.46 ≤≤ σσ2 ≤≤ 53.31

c. 2.08 ≤≤ σσ2 ≤≤ 16.7

d. 16.35 ≤≤ σσ2 ≤≤ 33.32

Solutions

Expert Solution

The 95% confidence interval estimate of the population variance 2 is:

n = sample size

s​​​​​​2​​​= sample variance &

2n-1,/2 and 2n-1,1-/2 is chi-square table value at (n-1) degrees of freedom and level of Significance for two tailed test.

In the given example,

n= sample size= 20

S = sample standard deviation= 5

S​​​​​​2= sample variance=25

= 5% level of Significance=0.05

From chi-square table,

2n-1,/2= 220-1,0.05/2=  219,0.025=32.852

2n-1,1-/2= 220-1,1-0.05/2= 219,0.975=8.91

The 95% confidence interval estimate of the population variance 2 is:

The 95% confidence interval estimate of the population variance 2 is :

The option (b) is the correct option.


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